[R] Data length mismatch.

Gabor Grothendieck ggrothendieck at gmail.com
Sun Jul 27 00:28:22 CEST 2008

Sorry, the last one should be:

ix <- match(B$DayOfYear, A$DayOfYear)
A[ix, "x"] <- A[ix, "x"] - B$x

Again we are assuming B's days are a subset of A's.

On Sat, Jul 26, 2008 at 6:08 PM, Gabor Grothendieck
<ggrothendieck at gmail.com> wrote:
> Here is a third solution.
> A[B$DayOfYear, "x"] <- A[B$DayOfYear, "x"] - B$x
> Its assumes B's days are a subset of A's but if that's not the case then
> you would need to intersect them first: ?intersect
> On Sat, Jul 26, 2008 at 5:26 PM,  <rkevinburton at charter.net> wrote:
>> I have two vectos (list) that represent a years of data.  Each "row" is represented by the day of year and the quantity that was sold for that day. I would like to form a new vector that is the difference between the two years of data. A sample of A (and similarly B) looks like:
>>> A[1:5,]
>>  DayOfYear    x
>> 1         1 1429
>> 2         2 3952
>> 3         3 3049
>> 4         4 2844
>> 5         5 2219
>> D <- A - B
>> This works just fine if A and B are both the same length. How is the best way to handle the situation where A and B are of different lengths? If the day of year exists in both vectors (lists) then I just want the coorespondng "row" in D to be the difference btween A and B values. If the "row" doesn't exist in either A or B then the difference should be treated as if the missing "row" was zero. Is this feasible?
>> Thank you.
>> Kevin
>> ______________________________________________
>> R-help at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.

More information about the R-help mailing list