[R] How to average minutes per hour per month in the form of '# hours #minutes'

[Jeff Newmiller]

This is a very unclear question. Weeks don't line up with months.. so you need to clarify how you would do this or at least give an explicit example of input data and result data.

On March 25, 2021 11:34:15 AM PDT, Dr Eberhard W Lisse <nospam using lisse.NA> wrote:
>Thanks, that is helpful.
>
>But, how do I group it to produce hours worked per week per month?
>
>el
>
>
>On 2021-03-25 19:03 , Greg Snow wrote:
>> Here is one approach:
>> 
>> tmp <- data.frame(min=seq(0,150, by=15))
>> 
>> tmp %>%
>>    mutate(hm=sprintf("%2d Hour%s %2d Minutes",
>>                      min %/% 60, ifelse((min %/% 60) == 1, " ", "s"),
>>                      min %% 60))
>> 
>> You could replace `sprintf` with `str_glue` (and update the syntax as
>> well) if you realy need tidyverse, but you would also loose some
>> formatting capability.
>> 
>> I don't know of tidyverse versions of `%/%` or `%%`.  If you need the
>> numeric values instead of a string then just remove the `sprintf` and
>> use mutate directly with `min %/% 60` and `min %% 60`.
>> 
>> This of course assumes all of your data is in minutes (by the time
>you
>> pipe to this code) and that all hours have 60 minutes (I don't know
>of
>> any leap hours.
>> 
>> On Sun, Mar 21, 2021 at 8:31 AM Dr Eberhard W Lisse <nospam using lisse.na>
>wrote:
>>>
>>> Hi,
>>>
>>> I have minutes worked by day (with some more information)
>>>
>>> which when using
>>>
>>>          library(tidyverse)
>>>          library(lubridate)
>>>
>>> run through
>>>
>>>          CONSMINUTES %>%
>>>                  select(datum, dauer) %>%
>>>                  arrange(desc(datum))
>>>
>>> look somewhat like
>>>
>>>          # A tibble: 142 x 2
>>>             datum      dauer
>>>             <date>     <int>
>>>           1 2021-03-18    30
>>>           2 2021-03-17    30
>>>           3 2021-03-16    30
>>>           4 2021-03-16    30
>>>           5 2021-03-16    30
>>>           6 2021-03-16    30
>>>           7 2021-03-11    30
>>>           8 2021-03-11    30
>>>           9 2021-03-11    30
>>>          10 2021-03-11    30
>>>          # … with 132 more rows
>>>
>>> I can extract minutes per hour
>>>
>>>          CONSMINUTES %>%
>>>          select(datum, dauer) %>%
>>>          group_by(week = format(datum, '%Y %V'))%>%
>>>          summarise_if(is.numeric, sum)
>>>
>>> and minutes per month
>>>
>>>          CONSMINUTES %>%
>>>          select(datum, dauer) %>%
>>>          group_by(month = format(datum, '%Y %m'))%>%
>>>          summarise_if(is.numeric, sum)
>>>
>>> I need to show the time worked per week per month in the format of
>>>
>>>          '# hours # minutes'
>>>
>>> and would like to also be able to show the average time per week per
>>> month.
>>>
>>> How can I do that (preferably with tidyverse :-)-O)?
>>>
>>> greetings, el
>>>
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>> 
>> 
>>
>
>______________________________________________
>R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
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>and provide commented, minimal, self-contained, reproducible code.

-- 
Sent from my phone. Please excuse my brevity.