[R] Using multiple dat files

[Bert Gunter]

Not quite sure if I understand you.

list.files() simply returns a character vector(not a list). You can simply
use a vector index to select whatever file you wish to read. So if your
desired filename is the 5th element of filelist above, something like

myfile <- read.table(filename[5], ...)

You can also use regular expressions to choose a bunch of files that have
some common signature to their names that you can read in simultaneously
using your "filelist" vector of names via something like:

myfiles <- lapply(grep("weath", filelist, value = TRUE), \(x)
read.table(x,...))
### Note that the result of lapply *is* a list, so use list indexing for
extraction from myfiles.


You can also choose files to read interactively (via a GUI interface) using
file.choose() instead of using list.files() if you prefer to do it that way.

Cheers,
Bert

On Wed, Nov 6, 2024 at 8:25 AM Sibylle Stöckli via R-help <
r-help using r-project.org> wrote:

> Dear community
>
> To import multiple .dat  weather files I am using list.files().
> I intend to use the R package “ClimInd” to calculate different
> agroclimatic indicators.
>
> Question: Is there another solution to import multiple .dat files so that
> I can select elements from the list, e.g. one specific weather file
> (example AAR_DailyWeather)?
>
>
> # Import multiple .dat files weather data
> filelist <- list.files(path =
> "O:/Data-Work/……./Daten_RA-MeteoCH_1990-2021", pattern='*.dat', all.files=
> T, full.names= T)
> W <- lapply(filelist, function(x) read.table(x, header = TRUE, sep = "",
> colClasses = "numeric", comment.char = ""))
> W[[1]]
>
> > dd(data = W[[1]]$Precip, time.scale = W[[1]]$year)
> Fehler in W[[1]]$year : $ operator is invalid for atomic vectors
>
> Kind regards
> Sibylle
>
>
>
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