[R] Extract estimate of error variance from glm() object
Rui Barradas
ru|pb@rr@d@@ @end|ng |rom @@po@pt
Wed Dec 25 09:23:45 CET 2024
Às 23:29 de 24/12/2024, Bert Gunter escreveu:
> ... but do note:
> glm(lot1 ~ log(u), data = clotting, family = gaussian)
>
> is a plain old *linear model*, which is of course a specific type of
> glm, but not one that requires the machinery of glm() to fit. That
> is, the above is exactly the same as:
>
> lm(lot1 ~ log(u), data = clotting)
>
> and gives exactly the same sigma() !
>
> (and I would therefore hazard the guess that the poster may
> misunderstand what a glm actually is, though of course I may be wrong
> about this).
>
> Cheers,
> Bert
>
> On Tue, Dec 24, 2024 at 5:45 AM Christofer Bogaso
> <bogaso.christofer using gmail.com> wrote:
>>
>> Hi,
>>
>> I have below GLM fit
>>
>> clotting <- data.frame(
>> u = c(5,10,15,20,30,40,60,80,100),
>> lot1 = c(118,58,42,35,27,25,21,19,18),
>> lot2 = c(69,35,26,21,18,16,13,12,12))
>> summary(glm(lot1 ~ log(u), data = clotting, family = gaussian))
>>
>> Is there any direct function to extract estimate of Error standard deviation?
>>
>> ______________________________________________
>> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide https://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
> ______________________________________________
> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide https://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
Hello,
In case of doubt, program a residual standard error function and compare
the results.
rse <- function(object) {
rss <- resid(object)^2
sum(rss / object[["df.residual"]]) |> sqrt()
}
clotting <- data.frame(
u = c(5,10,15,20,30,40,60,80,100),
lot1 = c(118,58,42,35,27,25,21,19,18),
lot2 = c(69,35,26,21,18,16,13,12,12))
fit1 <- glm(lot1 ~ log(u), data = clotting, family = gaussian)
fit2 <- lm(lot1 ~ log(u), data = clotting)
# all of the results below are identically equal
sigma(fit1)
rse(fit1)
sigma(fit2)
rse(fit2)
Hope this helps,
Rui Barradas
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