[R] [External] Error in percentage stacked barplot
Maria Lathouri
m|@thour| @end|ng |rom y@hoo@gr
Wed May 3 10:58:29 CEST 2023
Dear Richard,
Thank you very much for your reply. I went through the code and it worked. I was also able to change the colours.
I was wondering if I can change the legend position; instead of being in the bottom to be on the left side.
I tried the following but without any success
strip = FALSE
strip.right = TRUE
likert(t(hellisheidi), ReferenceZero=.5, xlab="X-lab", ylab="Y-lab", main="Stacked bar chart", col=c("#E94E1B", "#F7AA4E", "#BEBEBE", "#6193CE", "#00508C", "#E94E1B", "#BEBEBE"), legend.position="left")
Once again, thank you very much.
Kind regards,
Maria
Στις Τρίτη 2 Μαΐου 2023 στις 08:51:16 μ.μ. GMT+1, ο χρήστης Richard M. Heiberger <rmh using temple.edu> έγραψε:
## you may need to install HH
install.packagess("HH")
library(HH)
hellisheidi <- read.table(text="
Component Sample1 Sample2 Sample3
CaO 45 52 48
SiO2 25 22 18
Al2O3 15 11 14
TiO2 6 5 6
Na2O 5 4 5
CuO 3 3 5
Cl 1 3 4"
, header=TRUE, row.names="Component")
likert(t(hellisheidi), ReferenceZero=.5,
xlab="X-lab", ylab="Y-lab", main="Stacked bar chart")
> On May 2, 2023, at 15:23, Maria Lathouri via R-help <r-help using r-project.org> wrote:
>
> Dear all,
> I am trying to plot the following table in stacked barplot in percentages and also horizontal.
> Component Sample 1 Sample 2 Sample 3CaO 45 52 48SiO2 25 22 18Al2O3 15 11 14TiO2 6 5 6 Na2O 5 4 5CuO 3 3 5 Cl 1 3 4
> When I tried the following functionbarplot(data,
> + main = "Stacked bar chart",
> + sub = "Subtitle",
> + xlab = "X-lab",
> + ylab = "Y-lab",
> + axes = TRUE, horiz = TRUE)
> I got the following error
> Error in barplot.default(hellisheidi, main = "Stacked bar chart", sub = "Subtitle", :
> 'height' must be a vector or a matrix
> I also tried barplot(as.matrix(hellisheidi)) but what I was getting was the three stacked columns for Samples 1, 2 and 3 but I was getting an empty column for Component, instead of being the variable in the Samples.
>
>
> I was hoping if you could help me on that.
> Thank you very much in advance.
> Kind regards,Maria
>
>
>
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