[R] akima interp results to zero with less than 10 values
Duncan Murdoch
murdoch@dunc@n @end|ng |rom gm@||@com
Thu Jan 26 15:43:55 CET 2023
The akima package has a problematic license (it doesn't allow commercial
use), so it's been recommended that people use the interp package
instead. When I use interp::interp instead of akima::interp, I get
reasonable output from your example.
So that's another reason to drop akima...
Duncan Murdoch
On 26/01/2023 9:35 a.m., PIKAL Petr wrote:
> Dear all
>
> I have this table
>> dput(mat)
> mat <- structure(c(2, 16, 9, 2, 16, 1, 1, 4, 7, 7, 44.52, 42.8, 43.54,
> 40.26, 40.09), dim = c(5L, 3L))
>
> And I want to calculate result for contour or image plots as I did few years
> ago.
>
> However interp does not compute the z values and gives me zeros in z matrix.
> library(akima)
>
>> interp(mat[,1], mat[,2], mat[, 3], nx=5, ny=5)
> $x
> [1] 2.0 5.5 9.0 12.5 16.0
>
> $y
> [1] 1.0 2.5 4.0 5.5 7.0
>
> $z
> [,1] [,2] [,3] [,4] [,5]
> [1,] 0 0 0 0 0
> [2,] 0 0 0 0 0
> [3,] 0 0 0 0 0
> [4,] 0 0 0 0 0
> [5,] 0 0 0 0 0
>
> With the example from help page if less than 10 values are used, the result
> is also zero
> interp(akima$x[1:9], akima$y[1:9], akima$z[1:9], nx=5, ny=5)
>
> but with 10 or more values the result is correctly calculated
> interp(akima$x[1:10], akima$y[1:10], akima$z[1:10], nx=5, ny=5)
> $x
> [1] 0.0000 6.1625 12.3250 18.4875 24.6500
>
> $y
> [1] 1.24 5.93 10.62 15.31 20.00
>
> $z
> [,1] [,2] [,3] [,4] [,5]
> [1,] NA NA NA NA 34.60000
> [2,] NA NA 27.29139 27.11807 26.60971
> [3,] NA 19.81371 19.63614 19.12778 18.61943
> [4,] NA 14.01443 10.66531 11.13750 10.62914
> [5,] NA NA NA NA NA
>
> Help page says
> x, y, and z must be the same length (execpt if x is a
> SpatialPointsDataFrame) and may contain no fewer than ***four*** points.
>
> So my understanding was that 5 poins could be used but I am obviously wrong.
> Is it a bug in interp or in the documentation or is it my poor understanding
> of the whole matter.
>
> Best regards
> Petr
>
>
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