[R] is.na()<- on a character vector

[Bill Dunlap]

I think that
   is.na(x) <- i
generally does the same to x as does
   x[i] <- NA

I say 'generally' because some classes (e.g., numeric_version) do not allow
x[i]<-NA but do allow is.na(x)<-i.  It is possible that some classes mess
up this equivalence, but I think that would be considered a bug.

-Bill

On Fri, Dec 16, 2022 at 10:29 AM Göran Broström <goran.brostrom using umu.se>
wrote:

> I'm confused:
>
> > x <- 1:2
> > is.na(x) <- 1
> > x
> [1] NA  2
>
> OK, but
>
> > x <- c("A", "B")
> > is.na(x) <- "A"
> > x
>                A
> "A" "B"  NA
>
> What happens?
>
> G_ran
>
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