[R] Odd behavior of a function within apply

[Erin Hodgess]

OK.  I'm back again.

So my test1.df is 236x390

If I put in the following:
 lapply(test1.df,count1a)
Error in FUN(X[[i]], ...) : object 'y' not found
> lapply(test1.df,count1a)
Error in FUN(X[[i]], ...) : object 'y' not found
> sapply(test1.df,count1a)
Error in FUN(X[[i]], ...) : object 'y' not found
>
What am I doing wrong, please?
Thanks,
Erin


Erin Hodgess, PhD
mailto: erinm.hodgess using gmail.com


On Mon, Aug 8, 2022 at 1:41 PM Erin Hodgess <erinm.hodgess using gmail.com> wrote:

> Awesome, thanks so much!!
>
> Erin Hodgess, PhD
> mailto: erinm.hodgess using gmail.com
>
>
> On Mon, Aug 8, 2022 at 1:38 PM John Fox <jfox using mcmaster.ca> wrote:
>
>> Dear Erin,
>>
>> The problem is that the data frame gets coerced to a character matrix,
>> and the only column with "" entries is the 9th (the second one you
>> supplied):
>>
>> as.matrix(test1.df)
>>     X1_1_HZP1 X1_1_HBM1_mon X1_1_HBM1_yr
>> 1  "48160"   "December"    "2014"
>> 2  "48198"   "June"        "2018"
>> 3  "80027"   "August"      "2016"
>> 4  "48161"   ""            NA
>> 5  NA        ""            NA
>> 6  "48911"   "August"      "1985"
>> 7  NA        "April"       "2019"
>> 8  "48197"   "February"    "1993"
>> 9  "48021"   ""            NA
>> 10 "11355"   "December"    "1990"
>>
>> (Here, test1.df only contains the three columns you provided.)
>>
>> A solution is to use sapply:
>>
>>  > sapply(test1.df, count1a)
>>      X1_1_HZP1 X1_1_HBM1_mon  X1_1_HBM1_yr
>>              2             3             3
>>
>>
>> I hope this helps,
>>   John
>>
>>
>> On 2022-08-08 1:22 p.m., Erin Hodgess wrote:
>> > Hello!
>> >
>> > I have the following data.frame
>> >   dput(test1.df[1:10,8:10])
>> > structure(list(X1_1_HZP1 = c(48160L, 48198L, 80027L, 48161L,
>> > NA, 48911L, NA, 48197L, 48021L, 11355L), X1_1_HBM1_mon = c("December",
>> > "June", "August", "", "", "August", "April", "February", "",
>> > "December"), X1_1_HBM1_yr = c(2014L, 2018L, 2016L, NA, NA, 1985L,
>> > 2019L, 1993L, NA, 1990L)), row.names = c(NA, 10L), class = "data.frame")
>> >
>> > And the following function:
>> >> dput(count1a)
>> > function (x)
>> > {
>> >      if (typeof(x) == "integer")
>> >          y <- sum(is.na(x))
>> >      if (typeof(x) == "character")
>> >          y <- sum(x == "")
>> >      return(y)
>> > }
>> > When I use the apply function with count1a, I get the following:
>> >   apply(test1.df[1:10,8:10],2,count1a)
>> >      X1_1_HZP1 X1_1_HBM1_mon  X1_1_HBM1_yr
>> >             NA             3            NA
>> > However, when I do use columns 8 and 10, I get the correct response:
>> >   apply(test1.df[1:10,c(8,10)],2,count1a)
>> >     X1_1_HZP1 X1_1_HBM1_yr
>> >             2            3
>> >>
>> > I am really baffled.  If I use count1a on a single column, it works
>> fine.
>> >
>> > Any suggestions much appreciated.
>> > Thanks,
>> > Sincerely,
>> > Erin
>> >
>> >
>> > Erin Hodgess, PhD
>> > mailto: erinm.hodgess using gmail.com
>> >
>> >       [[alternative HTML version deleted]]
>> >
>> > ______________________________________________
>> > R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> > https://stat.ethz.ch/mailman/listinfo/r-help
>> > PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> > and provide commented, minimal, self-contained, reproducible code.
>> --
>> John Fox, Professor Emeritus
>> McMaster University
>> Hamilton, Ontario, Canada
>> web: https://socialsciences.mcmaster.ca/jfox/
>>
>>

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