[R] glm with family binomial and link identity
Martin Maechler
m@ech|er @end|ng |rom @t@t@m@th@ethz@ch
Thu Apr 28 16:48:14 CEST 2022
TLDR: No, there was no such change in R 4.2.0
>>>>> Ralf Goertz
>>>>> on Wed, 27 Apr 2022 10:27:33 +0200 writes:
> Hi,
> I just noticed that (with my version 4.2.0) it is no longer possible to
> use glm with family=binomial(link=identity). Why is that? It was
> possible with 4.0.x as a colleague of mine just confirmed.
That's not correct I think:
I've now tried your example in R versions 3.5.x, 4.0.5, 4.1.3, and 4.2.0
and it gave the same error everywhere:
d <- data.frame(y = c( 0, 1, 0, 1),
trt= c( 0, 0, 1, 1),
w = c(97, 3, 90, 10))
r0 <- try(
glm(y ~ trt, weights = w, data=d, family = binomial(link = identity))
)
## Error in binomial(link = identity) :
## link "identity" not available for binomial family; available links are ‘logit’, ‘probit’, ‘cloglog’, ‘cauchit’, ‘log’
And indeed, binomial() has started with
> head(binomial)
1 function (link = "logit")
2 {
3 linktemp <- substitute(link)
4 if (!is.character(linktemp))
5 linktemp <- deparse(linktemp)
6 okLinks <- c("logit", "probit", "cloglog", "cauchit", "log")
>
*forever*.
It is slightly interesting (to me at least) that if you use a string,
you can use all valid arguments for make.link() and not just
those that are declared "ok" by the code.
HOWEVER, this all has been documented for a long time,
in ?family == ?binomial
Note:
The ‘link’ and ‘variance’ arguments have rather awkward semantics
for back-compatibility. The recommended way is to supply them as
quoted character strings, but they can also be supplied unquoted
(as names or expressions). Additionally, they can be supplied as
a length-one character vector giving the name of one of the
options, or as a list (for ‘link’, of class ‘"link-glm"’). The
restrictions apply only to links given as names: when given as a
character string all the links known to make.link are accepted.
> After all it is useful to compute risk differences with factors.
at least it was neand
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