[R] flag records

[Bert Gunter]

Thanks ... and fair enough.
However, I disagree -- one is never too old for school.

Cheers,
Bert Gunter

"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )

On Tue, Apr 26, 2022 at 3:57 PM Val <valkremk using gmail.com> wrote:
>
> Hi Bert,
>
> I am too old for school.
>
>
>
>
> On Tue, Apr 26, 2022 at 5:41 PM Bert Gunter <bgunter.4567 using gmail.com> wrote:
> >
> > Sounds like homework. We try not to do homework here. See the posting
> > guide linked below for details.  (If not homework, let us know).
> >
> > Bert Gunter
> >
> > "The trouble with having an open mind is that people keep coming along
> > and sticking things into it."
> > -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
> >
> > On Tue, Apr 26, 2022 at 3:17 PM Val <valkremk using gmail.com> wrote:
> > >
> > > Hi All,
> > >
> > > I want to flag a record based on the following condition.
> > > The variables  in the sample data are
> > > State, name, day, text, ddate
> > >
> > > Sort the data by State, name, day ddate,
> > >
> > > Within  State, name, day
> > >     assign consecutive number for each row
> > >     find the date difference between consecutive rows,
> > >     if the difference is less than 50 days and the text string in
> > > previous and current rows  are the same then flag the record as X,
> > > otherwise Y.
> > >
> > > Here is  sample data and my attempt,
> > >
> > > DF<-read.table(text="State name day text ddate
> > >   CA A 1 xch 2014/09/16
> > >   CA A 2 xck 2015/5/29
> > >   CA A 2 xck 2015/6/18
> > >   CA A 2 xcm 2015/8/3
> > >   CA A 2 xcj 2015/8/26
> > >   FL B 3 xcu  2017/7/23
> > >   FL B 3 xcl  2017/7/03
> > >   FL B 3 xmc  2017/7/26
> > >   FL B 3 xca  2017/3/17
> > >   FL B 3 xcb  2017/4/8
> > >   FL B 4 xhh  2017/3/17
> > >   FL B 4 xhh  2017/1/29",header=TRUE)
> > >
> > >   DF$ddate   <- as.Date (as.Date(DF$ddate),  format="%Y/%m/%d" )
> > >   DF3         <- DF[order(DF$State,DF$name,DF$day,xtfrm(DF$ddate)), ]
> > >   DF3$C       <- with(DF3, ave(State, name, day, FUN = seq_along))
> > >   DF3$diff    <- with(DF3, ave(as.integer(ddate), State, name, day,
> > > FUN = function(x) x - x[1]))
> > >
> > > I stopped here, how do I evaluate the previous and the current rows
> > > text string and date difference?
> > >
> > > Desired result,
> > >
> > >
> > >      State name day text      ddate C diff flag
> > > 1     CA    A   1  xch 2014-09-16 1    0     y
> > > 2     CA    A   2  xck 2015-05-29 1    0      y
> > > 3     CA    A   2  xck 2015-06-18 2   20     x
> > > 4     CA    A   2  xcm 2015-08-03 3   66    y
> > > 5     CA    A   2  xcj 2015-08-26 4   89      y
> > > 9     FL    B   3  xca 2017-03-17 1    0      y
> > > 10    FL    B   3  xcb 2017-04-08 2   22    y
> > > 7     FL    B   3  xcl 2017-07-03 3   108     y
> > > 6     FL    B   3  xcu 2017-07-23 4  128    y
> > > 8     FL    B   3  xmc 2017-07-26 5  131   y
> > > 12    FL    B   4  xhh 2017-01-29 1    0     y
> > > 11    FL    B   4  xhh 2017-03-17 2   47    x
> > >
> > >
> > >
> > > Thank you,
> > >
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