[R] How to estimate the parameter for many variable?

[Jim Lemon]

Hi Siti,
I think we need a bit more information to respond helpfully. I have no
idea what "Ozone_weekly2" is and Google is also ignorant. "gev.fit" is
also unknown. The name suggests that it is the output of some
regression or similar. What function produced it, and from what
library? "ti" is known as you have defined it. However, I don't know
what you want to do with it. Finally, as this is a text mailing list,
we don't get any highlighting, so the text to which you refer cannot
be identified. I can see you have a problem, but cannot offer any help
right now.

Jim

On Thu, Jul 8, 2021 at 12:06 AM SITI AISYAH ZAKARIA
<aisyahzakaria using unimap.edu.my> wrote:
>
> Dear all,
>
> Can I ask something about programming in marginal distribution for spatial
> extreme?
> I really stuck on my coding to obtain the parameter estimation for
> univariate or marginal distribution for new model in spatial extreme.
>
> I want to run my data in order to get the parameter estimation value for 25
> stations in one table. But I really didn't get the idea of the correct
> coding. Here I attached my coding
>
> x <- data.matrix(Ozone_weekly2)
> x
> head(gev.fit)[1:4]
> ti = matrix(ncol = 3, nrow = 888)
> ti[,1] = seq(1, 888, 1)
> ti[,2]=sin(2*pi*(ti[,1])/52)
> ti[,3]=cos(2*pi*(ti[,1])/52)
> for(i in 1:nrow(x))
>   + { for(j in 1:ncol(x))
>     + {x[i,j] = 1}}
>
> My problem is highlighted in red color.
> And if are not hesitate to all. Can someone share with me the procedure,
> how can I map my data using spatial extreme.
> For example:
> After I finish my marginal distribution, what the next procedure. It is I
> need to get the spatial independent value.
>
> That's all
> Thank you.
>
> --
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