[R] Remove all factor levels from an R dataframe

[Jim Lemon]

Sure John,

df1<-df1[order(as.character(df1$year),decreasing=TRUE),]

Jim

On Tue, Nov 10, 2020 at 8:05 PM John <miaojpm using gmail.com> wrote:

> Thanks Jim. Can we do descending order?
>
> Jim Lemon <drjimlemon using gmail.com> 於 2020年11月10日 週二 下午4:56寫道：
>
>> Hi John,
>>
>> df1<-sapply(df1,as.character)
>>
>> Should do what you ask. The error message probably means that you should
>> do this:
>>
>> df1<-df1[order(as.character(df1$year)),]
>>
>> as "year" is the name of the first column in df1, not a separate object.
>>
>> Jim
>>
>> On Tue, Nov 10, 2020 at 6:57 PM John <miaojpm using gmail.com> wrote:
>>
>>> Hi,
>>>
>>>    I would like to sort the following simple dataframe by "year"
>>> (characters), but the factor structure prevents me from doing so. How
>>> can I
>>> remove the factor structure? Thanks!
>>>
>>> > df1
>>>   year                  country
>>> 4 2007             Asia; survey
>>> 5 2010 8 countries in E/SE Asia
>>> 6 2015                    Ghana
>>> 7
>>> 8 2000                      US?
>>> > str(df1)
>>> 'data.frame': 5 obs. of  2 variables:
>>>  $ year   : Factor w/ 9 levels "2017","2016",..: 4 5 3 6 7
>>>  $ country: Factor w/ 9 levels "Euro Area\\newline Testing the MP
>>> performance of the Euro Area",..: 4 5 6 7 8
>>> > df1[order(-year), ]
>>> Error in order(-year) : object 'year' not found
>>>
>>>         [[alternative HTML version deleted]]
>>>
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>>

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