[R] if else statement

[Jeff Newmiller]

To expand on Patrick's response...

You can use the expand.grid function to generate a test table containing all combinations. However, we would not be in a position to verify that the results you get when you apply your logic to the test table are what you want... you know the requirements much better than we do. Nor is that kind of service what this mailing list is for, so please focus on showing what you cannot figure out how to accomplish rather than asking us to do or check your work for you.

On May 4, 2020 10:33:12 AM PDT, "Patrick (Malone Quantitative)" <malone using malonequantitative.com> wrote:
>"I tried this but I am not sure if this is correct:"
>
>Does it provide the expected result for all possible combinations of
>1/2/NA
>for both variables?
>
>On Mon, May 4, 2020 at 1:16 PM Ana Marija <sokovic.anamarija using gmail.com>
>wrote:
>
>> Hello,
>>
>> I have a data frame like this:
>>
>> > head(b)
>>        FID   IID FLASER PLASER
>> 1: fam1000 G1000      1      1
>> 2: fam1001 G1001      1      1
>> 3: fam1003 G1003      1      2
>> 4: fam1005 G1005      1      1
>> 5: fam1009 G1009      NA      2
>> 6: fam1052 G1052      1      1
>> ...
>> > unique(b$PLASER)
>> [1]  1  2 NA
>> > unique(b$FLASER)
>> [1]  1  2 NA
>>
>> how can I do if else statement so that I am creating a
>> PHENO =2 if b$FLASER=2 or b$PLASER=2
>> PHENO=1 if b$FLASER=1 and b$PLASER=1
>> otherwise PHENO=NA
>>
>> I tried this but I am not sure if this is correct:
>> b$pheno=ifelse(b$PLASER==1 & b$FLASER==1,1,ifelse(b$PLASER==2 |
>> b$FLASER==2,2,NA))
>>
>> Thanks
>> Ana
>>
>>         [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>

-- 
Sent from my phone. Please excuse my brevity.