[R] NA command in a 'for' loop

[Helen Sawaya]

I have one column that represents correct response versus error (correct is coded as 1 and error is coded as 0). Nowhere else in the dataset are there values of 0. The vector is treated as an integer.
________________________________
From: Michael Dewey <lists using dewey.myzen.co.uk>
Sent: Monday, April 20, 2020 7:35 PM
To: Helen Sawaya <helensawaya using hotmail.com>; Rui Barradas <ruipbarradas using sapo.pt>; r-help using R-project.org <r-help using R-project.org>
Subject: Re: [R] NA command in a 'for' loop

Just a thought Helen but is x being treated as a real and what you think
are zero and are printed as zero are in fact some very small number? If
so you need to alter your test appropriately.

Michael

On 20/04/2020 17:25, Helen Sawaya wrote:
> Thank you for your reply.
>
> I tried d[] <- lapply(d, function(x) {is.na(x) <- x == 0; x})
> ​but I am still getting zeros instead of NAs in my output..
>
> I wonder if the problem is that some of my data files don't have any zeros (participants made no errors)..
> ________________________________
> From: Rui Barradas <ruipbarradas using sapo.pt>
> Sent: Monday, April 20, 2020 9:05 AM
> To: Helen Sawaya <helensawaya using hotmail.com>; r-help using R-project.org <r-help using R-project.org>
> Subject: Re: [R] NA command in a 'for' loop
>
> Hello,
>
> Instead of
>
> d[d == 0] <- NA
>
> try
>
> d[] <- lapply(d, function(x) {is.na(x) <- x == 0; x})
>
>
> Also, in the first for loop
>
> paste(i, sep = "")
>
> does nothing, it's the same as i.
> And the same for
>
> (d2$V4 == 1) == TRUE
>
> Since (d2$V4 == 1)  already is FALSE/TRUE there is no need for
>
> (.) == TRUE
>
>
> Hope this helps,
>
> Rui Barradas
>
>
>
> Às 20:52 de 19/04/20, Helen Sawaya escreveu:
>> Dear R experts,
>>
>> I am using a 'for' loop to apply commands to multiple datasets (each file is one participant). The only one not working is the command that identifies zeros in my datasets and changes them to NAs. But when I look at the output, zeros ("0") are still present. Surprisingly, the functions work fine when I apply them to a single dataset (outside the loop). I've tried:
>>
>> all.files <- list.files(".")
>> txt.files <- grep("threat.txt",all.files,value=T)
>>
>> for(i in txt.files){
>>     d <- read.table(paste(i,sep=""),header=F)
>>     d[d==0] <- NA #replace zeros with NA
>>     write.table(d, paste0(i,".tlbs.txt"), quote=FALSE, row.names=TRUE)}
>>     d<-d[ ,-c(10,11)]
>>     d2<-d[complete.cases(d), ]
>>     d2$V4<-as.numeric(d2$V4)
>>     congruent <- (d2$V4 == 1) == TRUE
>>     x <- get_tlbs(d2$V14, congruent, prior_weights = NULL, method = "weighted", fill_gaps = FALSE)
>>     write.table(x, paste0(i,".tlbs.txt"), quote=FALSE, row.names=TRUE)}
>>
>> I've also tried:
>>
>> for(i in txt.files){
>>     d <- read.table(paste(i,sep=""),header=F)
>>     if (0 %in% d)
>>     {replace_with_na(d,replace = list(x = 0))} # replace zeros with NA
>>     d<-d[ ,-c(10,11)]
>>     d2<-d[complete.cases(d), ]
>>     d2$V4<-as.numeric(d2$V4)
>>     congruent <- (d2$V4 == 1) == TRUE
>>     x <- get_tlbs(d2$V14, congruent, prior_weights = NULL, method = "weighted", fill_gaps = FALSE)
>>     write.table(x, paste0(i,".summaryoutput.txt"), quote=FALSE, row.names=TRUE)}
>>
>> Thank you for your help.
>> Sincerely
>> Helen
>>
>>         [[alternative HTML version deleted]]
>>
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>> and provide commented, minimal, self-contained, reproducible code.
>>
>
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>
> ______________________________________________
> R-help using r-project.org mailing list -- To UNSUBSCRIBE and more, see
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>

--
Michael
http://www.dewey.myzen.co.uk/home.html

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