[R] turning a list of objects into columns
Gerrit Draisma
gdr@|@m@ @end|ng |rom x@4@||@n|
Sun Jun 30 16:34:11 CEST 2019
Ha Janet,
Does this reshape do what you want:
df = read.table(header=TRUE,text="
scen streamflow trans evap psn
1 0.019234 1.658967 0.002883 0.002391
1 0.019027 1.661192 0.002844 0.003142
2 0.018821 1.695623 0.003192 0.002167
2 0.018619 1.503481 0.002536 0.003059
3 0.018425 0.000008 1.880355 0.002592
3 0.018369 0.100551 2.225793 0.006642
")
df$t <- 1:2
# reshape(df,idvar="scen",timevar="t",direction="wide")
reshape(df,idvar="t",timevar="scen",direction="wide")
HTH, Gerrit
> Date: Sat, 29 Jun 2019 12:45:46 -0700
> From: Jeff Newmiller <jdnewmil using dcn.davis.ca.us>
>
> Maybe look at reshape2? e.g. https://seananderson.ca/2013/10/19/reshape/
>
> There is a very capable base R reshape function, but I find it quite
> challenging to apply.
>
> Note that you normally want to retain one or more columns to identify
> each row in your result... but I am not sure I see anything suitable
> in your example data. You may have removed it, or it may have been
> implied and you may need to create something that will do the job.
>
> e.g. https://www.studytonight.com/dbms/database-key.php
>
> On June 29, 2019 11:27:40 AM PDT, Janet Choate <jsc.eco using gmail.com> wrote:
> > Hi,
> > I have a data frame that looks something like this (but much longer):
> > df
> > scen streamflow trans evap psn
> > 1 0.019234 1.658967 0.002883 0.002391
> > 1 0.019027 1.661192 0.002844 0.003142
> > 2 0.018821 1.695623 0.003192 0.002167
> > 2 0.018619 1.503481 0.002536 0.003059
> > 3 0.018425 0.000008 1.880355 0.002592
> > 3 0.018369 0.100551 2.225793 0.006642
> >
> > i want to end up with something like this (for each variable -
> > streamflow,
> > trans, evap, psn). using the variable trans here as an example:
> > trans1 trans2 trans3
> > 1.658967 1.695623 0.000008
> > 1.661192 1.503481 0.100551
> >
> > so that each variable (streamflow, trans, evap, psn) is in a separate
> > column based on the scen #.
>
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