[R] Output of arima
William Dunlap
wdunl@p @ending from tibco@com
Tue Nov 13 18:36:52 CET 2018
Try supplying the order argument to arima. It looks like the default is to
estimate only the mean.
> arima(b, order=c(1,0,0))
Call:
arima(x = b, order = c(1, 0, 0))
Coefficients:
ar1 intercept
0.8871 0.2369
s.e. 0.0145 0.2783
sigma^2 estimated as 1.002: log likelihood = -1420.82, aic = 2847.63
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Tue, Nov 13, 2018 at 4:02 AM, Ashim Kapoor <ashimkapoor using gmail.com> wrote:
> Dear All,
>
> Here is a reprex:
>
> set.seed(123)
> b <- arima.sim(list(order = c(1,0,0),ar= .9),n=1000,sd=1)
> arima(b)
>
> Call:
> arima(x = b)
>
> Coefficients:
> intercept
> 0.2250
> s.e. 0.0688
>
> sigma^2 estimated as 4.735: log likelihood = -2196.4, aic = 4396.81
> >
>
> Should sigma^2 not be equal to 1 ? Where do I misunderstand ?
>
> Many thanks,
> Ashim
>
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>
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