[R] about reading files in order

[Henrik Bengtsson]

You can use:

> files <- list.files(path = "folder01")
> files <- gtools::mixedsort(files)

to order the files in a "human-friendly" order rather than
lexicographic order (which sort() provides).

FYI 1; it's preferred to use file.path("folder01", list[i]) rather
than paste('folder01',lists[i],sep='/').

FYI 2; if you use list.files(path = "folder01", full.names = TRUE),
you get the full paths rather name just the file names, i.e. you don't
have to use file.path().

/Henrik

On Thu, Jun 29, 2017 at 12:04 PM, lily li <chocold12 at gmail.com> wrote:
> Hi R users,
> I have a question about opening the txt files and putting them into a
> matrix. The txt files are in the folder01, while they have the name
> file.1.txt, file.2.txt, file.3.txt, etc. There are about 200 such text
> files. Each txt file contains one value inside. When I tried to use the
> code below, I found that the txt files are not in order, from 1, 2, 3, to
> 200. Rather, they are in the order 1, 10, 100, 101, etc. How to change it
> so that they are in order? Thanks for your help.
>
> temp <- list.files('folder01',pattern="*.txt"
> name.list <-lapply(paste('folder01',temp,sep='/'),read.table,head=F)
> library(data.table)
> files.matrix <-rbindlist(name.list)
>
> Also, when use the code below, how to complete it so that the values of the
> files are stored in a matrix?
> lists = list.files('folder01')
> for (i in 1:length(lists)){
>   file <- read.table(paste('folder01',lists[i],sep='/'),head=F)
>   print(file)
> }
>
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>
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