[R] Efficient swapping

[Jeff Newmiller]

No, that would remap B to A. Convert to character before doing this, then back to factors. 
-- 
Sent from my phone. Please excuse my brevity.

On July 6, 2017 4:43:00 PM PDT, Ista Zahn <istazahn at gmail.com> wrote:
>Untested, but I expect that setting the levels to be the same across
>the
>two factors
>
>levels(tmp$R1) <- levels(tmp$R2) <- LETTERS[1:6]
>
>and proceeding as before should be fine.
>
>Best,
>Ista
>
>On Jul 6, 2017 6:54 PM, "Gang Chen" <gangchen6 at gmail.com> wrote:
>
>Thanks a lot, Ista! I really appreciate it.
>
>How about a slightly different case as the following:
>
>set.seed(1)
>(tmp <- data.frame(x = 1:10, R1 = sample(LETTERS[1:5], 10, replace =
> TRUE), R2 = sample(LETTERS[2:6], 10, replace = TRUE)))
>
>   x R1 R2
>   1  C  B
>   2  B  B
>   3  C  E
>   4  E  C
>   5  E  B
>   6  D  E
>   7  E  E
>   8  D  F
>   9  C  D
>  10  A  E
>
>Notice that the factor levels between the two factors, R1 and R2,
>slide by one level; that is, factor R1 does not have level F while
>factor R2 does not have level A. I want to swap the factor levels
>based on the combined levels of the two factors as shown below:
>
>tl <- unique(c(levels(tmp$R1), levels(tmp$R2)))
>for(ii in 1:dim(tmp)[1]) {
>   kk <- which(tl %in% tmp[ii,'R2'], arr.ind = TRUE) - which(tl %in%
>      tmp[ii,'R1'], arr.ind = TRUE)
>   if(kk%%2!=0) { # swap the their levels between the two factors
>      qq <- tmp[ii,]$R1
>      tmp[ii,]$R1 <- tmp[ii,]$R2
>      tmp[ii,]$R2 <- qq
>  }
>}
>
>How to go about this case? Thanks!
>
>
>On Thu, Jul 6, 2017 at 5:16 PM, Ista Zahn <istazahn at gmail.com> wrote:
>> How about
>>
>> foo <- with(list(r1 = tmp$R1,
>>                  r2 = tmp$R2,
>>                  swapme = (as.numeric(tmp$R1) - as.numeric(tmp$R2))
>%% 2
>!= 0),
>> {
>>     tmp[swapme, "R1"] <- r2[swapme]
>>     tmp[swapme, "R2"] <- r1[swapme]
>>     tmp
>> })
>>
>> Best,
>> Ista
>>
>> On Thu, Jul 6, 2017 at 4:06 PM, Gang Chen <gangchen6 at gmail.com>
>wrote:
>>> Suppose that we have the following dataframe:
>>>
>>> set.seed(1)
>>> (tmp <- data.frame(x = 1:10, R1 = sample(LETTERS[1:5], 10, replace =
>>> TRUE), R2 = sample(LETTERS[1:5], 10, replace = TRUE)))
>>>
>>>     x R1 R2
>>> 1   1  B  B
>>> 2   2  B  A
>>> 3   3  C  D
>>> 4   4  E  B
>>> 5   5  B  D
>>> 6   6  E  C
>>> 7   7  E  D
>>> 8   8  D  E
>>> 9   9  D  B
>>> 10 10  A  D
>>>
>>> I want to do the following: if the difference between the level
>index
>>> of factor R1 and that of factor R2 is an odd number, the levels of
>the
>>> two factors need to be switched between them, which can be performed
>>> through the following code:
>>>
>>> for(ii in 1:dim(tmp)[1]) {
>>>    kk <- which(levels(tmp$R2) %in% tmp[ii,'R2'], arr.ind = TRUE) -
>>> which(levels(tmp$R1) %in% tmp[ii,'R1'], arr.ind = TRUE)
>>>    if(kk%%2!=0) { # swap the their levels between the two factors
>>>       qq <- tmp[ii,]$R1
>>>       tmp[ii,]$R1 <- tmp[ii,]$R2
>>>       tmp[ii,]$R2 <- qq
>>>   }
>>> }
>>>
>>> More concise and efficient way to do this?
>>>
>>> Thanks,
>>> Gang
>>>
>>> ______________________________________________
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>>> PLEASE do read the posting guide http://www.R-project.org/
>posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>
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>
>______________________________________________
>R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
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>PLEASE do read the posting guide
>http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.