[R] Function that works within a package and not when copied in global environment. Why?
    Marc Girondot 
    marc_grt at yahoo.fr
       
    Thu Feb  2 15:30:57 CET 2017
    
    
  
Dear experts,
In the package nlWaldTest, there is an hidden function : .smartsub
I can use it, for example:
 > getFromNamespace(".smartsub", ns="nlWaldTest")(pat="x", repl="b" ,
x="essai(b[1], b[2], x[1])")
[1] "essai(b[1], b[2], b[1])"
Now I try to create this function in my global environment:
smartsub <- getFromNamespace(".smartsub", ns="nlWaldTest")
It works also:
 > smartsub(pat="x", repl="b" , x="essai(b[1], b[2], x[1])")
[1] "essai(b[1], b[2], b[1])"
But if I create the function manually:
 > smartsub2 <- function (pat, repl, x)
  {
      args <- lapply(as.list(match.call())[-1L], eval, parent.frame())
      names <- if (is.null(names(args)))
          character(length(args))
      else names(args)
      dovec <- names %in% vectorize.args
      do.call("mapply", c(FUN = FUN, args[dovec], MoreArgs = 
list(args[!dovec]),
                          SIMPLIFY = SIMPLIFY, USE.NAMES = USE.NAMES))
  }
 > smartsub2(pat="x", repl="b" , x="essai(b[1], b[2], x[1])")
Error in names %in% vectorize.args : objet 'vectorize.args' introuvable
It fails because vectorize.args is unknown
Indeed smartsub2 is different from smartsub.
 > identical(smartsub, smartsub2)
[1] FALSE
1/ Why are they different? They are just a copy of each other.
2/ Second question, vectorize.args is indeed not defined before to be 
used in the function. Why no error is produced in original function?
Thanks a lot
Marc
-- 
__________________________________________________________
Marc Girondot, Pr
Laboratoire Ecologie, Systématique et Evolution
Equipe de Conservation des Populations et des Communautés
CNRS, AgroParisTech et Université Paris-Sud 11 , UMR 8079
Bâtiment 362
91405 Orsay Cedex, France
Tel:  33 1 (0)1.69.15.72.30   Fax: 33 1 (0)1.69.15.73.53
e-mail: marc.girondot at u-psud.fr
Web: http://www.ese.u-psud.fr/epc/conservation/Marc.html
Skype: girondot
    
    
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