[R] how do I define a function which is equivalent to `deparse(substitute(x))`?

Jeff Newmiller jdnewmil at dcn.davis.ca.us
Sun Dec 11 09:46:23 CET 2016

No. Read Hadley Wickham's "Advanced R" to learn why not. 
Sent from my phone. Please excuse my brevity.

On December 10, 2016 10:24:49 PM PST, frederik at ofb.net wrote:
>Dear R-Help,
>I asked this question on StackOverflow,
>but thought perhaps R-help would be more appropriate.
>I want to write a function in R which grabs the name of a variable
>from the context of its caller's caller. I think the problem I have is
>best understood by asking how to compose `deparse` and `substitute`.
>You can see that a naive composition does not work:
>    # a compose operator
>    >  `%c%` = function(x,y)function(...)x(y(...))
>    # a naive attempt to combine deparse and substitute
>    > desub = deparse %c% substitute
>    > f=function(foo) { message(desub(foo)) }
>    > f(log)
>    foo
>    # this is how it is supposed to work
>    > g=function(foo) { message(deparse(substitute(foo))) }
>    > g(log)
>    log
>Is there a way I can define a function `desub` so that `desub(x)` has
>the same value as `deparse(substitute(x))` in every context?
>Thank you,
>Frederick Eaton
>R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see
>PLEASE do read the posting guide
>and provide commented, minimal, self-contained, reproducible code.

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