[R] How to split 32 bits data into 16 bit or 8 bit data

[Frank Wang]

Thank you very much that substr works great on my data. For future users, I
did in the following code.

z<-matrix(c(substr(tmp,5,8),substr(tmp,1,4)),5,2)
dataU16 <- c(t(z))



On Sun, Nov 22, 2015 at 8:38 AM, Duncan Murdoch <murdoch.duncan at gmail.com>
wrote:

> On 22/11/2015 2:04 AM, Frank Wang wrote:
>
>> Hi,
>>
>> I am new user on R. I want to split a vector of hex data such as
>> "00ff8020"
>> "02d00000" "001e0240" "00010096" "00010033"
>> into 16 bits such as:
>> "00ff", "8020", "02d0","0000","001e", "0240", "0001","0096", "0001",
>> "0033"
>>
>> Are there any way to do it?
>>
>
> If those are really strings, use substr().
>
> If they are 32 bit integers, you could use x %% (2^16) for the low 16
> bits.  For the high 16 bits, you'll have to be careful about the sign. Or
> you could use the bitops package, bitShiftR(x, 16).  In either case the
> results will display by default in decimal; if you want a hex display, use
> as.hexmode().
>
> Duncan Murdoch
>
>

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