[R] Count number in r

John Kane jrkrideau at inbox.com
Tue May 19 17:57:19 CEST 2015


And another approach just for the heck of it.

library(plyr)

# where dat1 is your data 
dd1  <-  subset(dat1, Rain >= .01)

dd1$Year  <-  as.factor(dd1$Year)
dd1$Month  <-  as.factor(dd1$Month)

count (dd1, .(Year, Month))

John Kane

Kingston ON Canada


> -----Original Message-----
> From: hafizuddinarshad21 at gmail.com
> Sent: Tue, 19 May 2015 03:10:32 -0700
> To: r-help at r-project.org
> Subject: [R] Count number in r
> 
> Dear R users,
> 
> Could someone help me on this? I have this kind of data set:
> 
> structure(list(Year = c(1971L, 1971L, 1971L, 1971L, 1971L, 1971L,
> 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L,
> 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L,
> 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L,
> 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L,
> 1971L, 1971L), Month = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
> 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
> 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
> 2L, 2L, 2L), Rain = c(58.9, 74.6, 17.7, 7.8, 1.2, 1, 5.3, 0.7,
> 1.2, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
> 0, 10.4, 17.5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0)), .Names =
> c("Year",
> "Month", "Rain"), class = "data.frame", row.names = c(NA, -44L
> ))
> 
> I want to count data in "Rain" that is greater and equal to 0.1 mm
> according to their "Month" and "Year". I have used this code, but it
> seems
> so wrong.
> 
> raindat <- read.csv('my data set',header=TRUE)
> yearcorr<-min(raindat$Year)-1
> years<-unique(raindat$Year)
> rainmonth<-as.data.frame(matrix(0,nrow=2,ncol=12))
> for(year in years) {
>   for(month in 1:12) {
>     if(any(raindat$Year==year&raindat$Month==month))
>       rainmonth[year-yearcorr,month]<-
>       length((which(raindat$Rain >=
> 0.1))[raindat$Year==year&raindat$Month==month])
>   }
> }
> rownames(rainmonth)<-years
> names(rainmonth)<-month.abb
> rainmonth
> 
> Thank you so much.
> 
> 
> Arshad
> 
> 	[[alternative HTML version deleted]]
> 
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