[R] dplyr help

[Brian Kreeger]

​dplyr solution:

bevs %>% group_by(name, sex, drink) %>% summarise(​cost = sum(cost)) %>%
select(name, drink, cost, sex)

The last select statement puts the output in the column order you wanted in
your result.

I hope this helps.

Brian



On Wed, Jul 29, 2015 at 9:37 PM, Jon BR <jonsleepy at gmail.com> wrote:

> Hello,
>     I've recently discovered the helpful dplyr package.  I'm using the
> 'aggregate' function as such:
>
>
> bevs <- data.frame(cbind(name = c("Bill", "Mary"), drink = c("coffee",
> "tea", "cocoa", "water"), cost = seq(1:8), sex = c("male","female")));
> bevs$cost <- seq(1:8)
>
> > bevs
>   name  drink cost    sex
> 1 Bill coffee    1   male
> 2 Mary    tea    2 female
> 3 Bill  cocoa    3   male
> 4 Mary  water    4 female
> 5 Bill coffee    5   male
> 6 Mary    tea    6 female
> 7 Bill  cocoa    7   male
> 8 Mary  water    8 female
> >
>
> > aggregate(cost ~ name + drink, data = bevs, sum)
>   name  drink cost
> 1 Bill  cocoa   10
> 2 Bill coffee    6
> 3 Mary    tea    8
> 4 Mary  water   12
>
> My issue is that I would like to keep a column for 'sex', for which there
> is a 1:1 mapping with 'name', such that every time 'Bill' appears, it is
> always 'male'.
>
> Does anyone know of a way to accomplish this, with or without dplyr?  The
> ideal command(s) would produce this:
>
>   name  drink cost sex
> 1 Bill  cocoa   10   male
> 2 Bill coffee    6   male
> 3 Mary    tea    8   female
> 4 Mary  water   12   female
>
> I would be thankful for any suggestion!
>
> Thanks,
> Jonathan
>
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>
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