[R] Density plots for Chi-square and F-distribution on my data

[varin sacha]

Arg, just been caught !
No, just joking, it is a long time I don't have homework anymore. I keep on giving myself homeworks life long yes this is true. 
Anyways thanks for your response.
Best,




----- Mail original -----
De : Bert Gunter <gunter.berton at gene.com>
À : varin sacha <varinsacha at yahoo.fr>
Cc : "r-help at r-project.org" <r-help at r-project.org>
Envoyé le : Jeudi 19 février 2015 17h51
Objet : Re: [R] Density plots for Chi-square and F-distribution on my data

I think you might do well to consult a local statistical expert, as
you appear to be out of your statistical depth here.

Also, is this homework? If so, this is not a homework site (although
posters sometimes get help anyway).

Cheers,
Bert

Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374

"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
Clifford Stoll





On Thu, Feb 19, 2015 at 8:36 AM, varin sacha <varinsacha at yahoo.fr> wrote:
> Dear R-helpers,
>
> I want to compute the density plot (probability plot) of the Chi-square distribution.
> My 2 categorical variables are gender (male, female) and colors of the eyes (blue, green and brown).
>
> The sample size n = 100. The proportions are the following :
>
> male and blue eyes : 10%
> male and green eyes : 20%
> male and brown eyes : 22%
> female and blue eyes : 20%
> female and green eyes : 13%
> female and brown eyes : 15%
>
> There are k-1 df = 6-1= 5
>
> I don't know how to take into consideration the percents here above in my R code here below ?
>
> x <- rchisq(100, 5)
> hist(x, prob=TRUE)
> curve( dchisq(x, df=5), col='red', add=TRUE)
>
>
> Second point, I want to do the same, to compute the density plot, but this time for the Fisher distribution.
> My categorical variable is gender again (male, female)
> My numerical variable is the mark in Mathematics test (3; 4; 5; 5.5)
> The proportions are the following :
> male and 3 : 10%
> male and 4 : 15%
> male and 5 : 10%
> male and 5.5 : 15%
> female and 3 : 12%
> female and 4: 0%
> female and 5 : 25%
> female and 5.5 : 13%
>
> There are df1=2-1= 1 and df2=8-2= 6
>
> Again, I don't know how to take into consideration the percents here above in my R code here below ?
>
>
> df(100, 1, 6, log = FALSE)
> x <- rf(100, 1, 6)
> hist(x, prob=TRUE)
> curve( df(x,1,6), col='red', add=TRUE)
>
> Best,
> Thanks for your help.
>
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