[R] F Distribution

Fraser D. Neiman fneiman at monticello.org
Mon Dec 21 20:55:58 CET 2015


Dear Bob,

You want...

> qf( .95,1, 1)
[1] 161.4476

Best, Fraser

-----Original Message-----
From: Robert Sherry [mailto:rsherry8 at comcast.net] 
Sent: Monday, December 21, 2015 2:51 PM
To: R Project Help
Subject: [R] F Distribution


When I use a table, from a Schaum book, I see that for the 95 percentile, with v_1 = 1 and v_2 = 1 the value is 161. In the modern era, looking values up in a table is less than ideal. Therefore, I would expect R to have a function to do this and based upon my reading of the documentation, I would expect the following call to get the value I expect:
      pf( .95,1, 1)
However, it produces
     0.4918373
Therefore, I conclude that I am using the wrong function. What function should I use?

Thanks
Bob

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