[R] subset every 5th row

[arun]

Hi Veepsirtt,
May be this helps:

dat1 <- structure(list(V2 = c(11109.75, 11135.15, 11105.85, 11099.75, 
11055.55, 11063.45, 11045.65, 11065, 11061.2, 11070.25, 11069.3, 
11076, 11081.85, 11086.4, 11086.7, 11065.6, 11071.25, 11073.15, 
11077.8, 11067.7, 11061.1, 11065.9, 11069.1, 11063.3, 11070.45, 
11074.4, 11069.4, 11063.65, 11067.05, 11070.1, 11074, 11069.6, 
11072.65, 11073.7, 11061.35, 11064.2, 11066.85, 11078.15, 11079.65, 
11079.5, 11075.9, 11066.95, 11072.55, 11068.85, 11073.5, 11067.6, 
11055.3, 11053.3, 11052.65, 11047.6, 11045.25, 11028.9, 11036.15, 
11034.3, 11044.05, 11030.65, 11036.6, 11039.75, 11035.35, 11019.05
)), .Names = "V2", class = "data.frame", row.names = c(NA, 60L
))
dat1[seq(5,nrow(dat1),by=5),,drop=FALSE]
#or
dat1[((seq(nrow(dat1))-1)%%5+1)==5,,drop=FALSE]

A.K.




On Sunday, January 19, 2014 9:40 AM, "veepsirtt at gmail.com" <veepsirtt at gmail.com> wrote:

Hi A.K sir

1,11109.75
2,11135.15
3,11105.85
4,11099.75
5,11055.55
6,11063.45
7,11045.65
8,11065
9,11061.2
10,11070.25
11,11069.3
12,11076
13,11081.85
14,11086.4
15,11086.7
16,11065.6
17,11071.25
18,11073.15
19,11077.8
20,11067.7
21,11061.1
22,11065.9
23,11069.1
24,11063.3
25,11070.45
26,11074.4
27,11069.4
28,11063.65
29,11067.05
30,11070.1
31,11074
32,11069.6
33,11072.65
34,11073.7
35,11061.35
36,11064.2
37,11066.85
38,11078.15
39,11079.65
40,11079.5
41,11075.9
42,11066.95
43,11072.55
44,11068.85
45,11073.5
46,11067.6
47,11055.3
48,11053.3
49,11052.65
50,11047.6
51,11045.25
52,11028.9
53,11036.15
54,11034.3
55,11044.05
56,11030.65
57,11036.6
58,11039.75
59,11035.35
60,11019.05
thanks
veepsirtt


_____________________________________
Sent from http://r.789695.n4.nabble.com