[R] Replace element with pattern

jim holtman jholtman at gmail.com
Fri Nov 1 12:47:52 CET 2013

try this:

> x <- rbind("Peak Usage    : init:2359296, used:15859328, committed:15892480,max:50331648Current Usage : init:2359296, used:15857920,committed:15892480, max:50331648|-------------------|")
> apply(x, 1, function(a) sub("(Current.*?[/|]).*", "\\1", a))
[1] "Peak Usage    : init:2359296, used:15859328,
committed:15892480,max:50331648Current Usage : init:2359296,
used:15857920,committed:15892480, max:50331648|"

Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.

On Fri, Nov 1, 2013 at 4:09 AM,  <mohan.radhakrishnan at polarisft.com> wrote:
> Hi,
>          I have a data frame with one column and several rows of the form.
> "Peak Usage    : init:2359296, used:15859328, committed:15892480,
> max:50331648Current Usage : init:2359296, used:15857920,
> committed:15892480, max:50331648|-------------------|"
> I tested the regex
>  Current.*?[\|]
> in an online tester which greedily matches upto the first 'pipe' character
> Current Usage : init:2359296, used:15857920, committed:15892480,
> max:50331648|
> This is what I want.
> I tried to replace the entire rows using
> apply( y, 1, function(x) gsub(x,"Current.*?[/|]",x)) which didn't work.
> How is this done ? I also want to recursively apply some more patterns one
> by one on the rows till I reduce it to exactly what I want. Is there a way
> to do this without loops ?
> Thanks,
> Mohan
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