[R] convert a character string to a name
Blaser Nello
nblaser at ispm.unibe.ch
Thu May 23 09:29:49 CEST 2013
If you want to use the character string:
attach(dftest)
aggregate(cbind(sapply(x_test, get))~z, data=dftest, FUN=mean)
# or
with(dftest,aggregate(cbind(sapply(x_test, get)),list(z),FUN=mean))
detach(dftest)
Cheers,
Nello
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of arun
Sent: Donnerstag, 23. Mai 2013 09:19
To: jpm miao
Cc: R help
Subject: Re: [R] convert a character string to a name
with(dftest,aggregate(cbind(x,y),list(z),FUN=mean))
# Group.1 x y
#1 0 7 1
#2 1 6 2
#or
library(plyr)
ddply(dftest,.(z),numcolwise(mean))
# z x y
#1 0 7 1
#2 1 6 2
A.K.
----- Original Message -----
From: jpm miao <miaojpm at gmail.com>
To: r-help <r-help at r-project.org>
Cc:
Sent: Thursday, May 23, 2013 3:05 AM
Subject: [R] convert a character string to a name
Hi,
From time to time I need to do the aggregation. To illustrate, I present a toy example as below. In this example, the task is to aggregate x and y by z with the function mean.
Could I call the aggregation function with x_test, where
x_test=c("x","y")? Thanks
Miao
> dftest<-data.frame(x=1:12, y=(1:12)%%4, z=(1:12)%%2) dftest
x y z
1 1 1 1
2 2 2 0
3 3 3 1
4 4 0 0
5 5 1 1
6 6 2 0
7 7 3 1
8 8 0 0
9 9 1 1
10 10 2 0
11 11 3 1
12 12 0 0
> aggregate(cbind(x,y)~z, data=dftest, FUN=mean)
z x y
1 0 7 1
2 1 6 2
> x_test=c("x","y")
> aggregate(cbind(x_test)~z, data=dftest, FUN=mean)
Error in model.frame.default(formula = cbind(x_test) ~ z, data = dftest) :
variable lengths differ (found for 'z') a1aggregate(cbind(factor(x_test))~z, data=dftest, FUN=mean) Error in model.frame.default(formula = cbind(factor(x_test)) ~ z, data =
dftest) :
variable lengths differ (found for 'z')
> aggregate(factor(x_test)~z, data=dftest, FUN=mean)
Error in model.frame.default(formula = factor(x_test) ~ z, data = dftest) :
variable lengths differ (found for 'z')
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