[R] error in unique() command

[Uwe Ligges]

On 15.02.2013 13:05, Amir Kasaeian wrote:
> Dear all,
> Good day!
>
> I have a question in my codes, would you please help me how to rectify it?
> these are my coded but at the last line I received the error!
>
> mac_30 = read.dta("MAC results4.dta")
> mac_30
> map_30 = read.dta("MAP results4.dta")
> map_30
> mac_30$weight = 1/nrow(mac_30)
> mac_30
> map_30$weight = 1/nrow(map_30)
> map_30
> input.data = merge(mac_30, map_30, all = TRUE)
> input.data.no15to19 = subset(input.data, agegroup != "15-19" | is.na(agegroup))
> input.data.no15to19
> fit = loess(v5q0 ~ year, input.data.no15to19, weights = weight, span = 0.5)
>
> years.predict = seq(min(input.data.no15to19$year), max(input.data.no15to19$year))
>
> combined.method = data.frame(iso3 = unique(input.data$iso3), svdate = unique(input.data$svdate), method = "Combined method", year = years.predict)
> the error is:
>
> Error in data.frame(iso3 = unique(input.data3$iso3), svdate =unique(input.data3$svdate),  :
>    arguments imply differing number of rows: 1, 4, 45


Yes, unique() resulted in vectors of different lengths in your case, 
that cannot be combined in a data.frame.

Uwe Ligges

>
> I know there is only one iso3 and 4 years but what I need is forty five 1 and forty five rows of different 4 svdate exactly equivalent to forty five rows of different years.
>   Now, how can I have the same number of rows for the different variable to continue my code for rest of analysis?
>
> Thank you so much.
>
> Kind regards,
> Amir
>
>
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