[R] The interpretation of lm(y~x)?
Bert Gunter
gunter.berton at gene.com
Wed Feb 6 20:22:52 CET 2013
Have you read An Introduction to R or other R tutorial? DO you know
about ordered factors and contrasts in linear models?
-- Bert
On Wed, Feb 6, 2013 at 5:00 AM, jing tang <gimmytang at gmail.com> wrote:
> Hi,
> I am reading the book "Mixed Effects Models in S and S-Plus" and come
> across an example with the Rail data.
> I tried to use lm(travel~Rail,data=Rail) and got the following result:
>
> Call:
> lm(formula = travel ~ Rail, data = Rail)
>
> Residuals:
> Min 1Q Median 3Q Max
> -6.6667 -1.0000 0.1667 1.0000 6.3333
>
> Coefficients:
> Estimate Std. Error t value Pr(>|t|)
> (Intercept) 66.5000 0.9477 70.169 < 2e-16 ***
> Rail.L 54.3032 2.3214 23.392 2.22e-11 ***
> Rail.Q -4.6917 2.3214 -2.021 0.066161 .
> Rail.C -2.6584 2.3214 -1.145 0.274458
> Rail^4 -0.5669 2.3214 -0.244 0.811181
> Rail^5 11.1919 2.3214 4.821 0.000418 ***
> ---
> Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
>
>
> I wonder how the model is represented. Is it correct to write: Travel =
> beta1 + beta2*Rail + error? Beta1 should be Intercept which is clear to me.
> But how to link beta2 with the coefficients Rail.L, Rail.Q, Rail.C, Rail^4
> and Rail^5 shown in the result?
>
> Thanks for your comments,
>
> Best,
> Jing
>
> [[alternative HTML version deleted]]
>
>
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--
Bert Gunter
Genentech Nonclinical Biostatistics
Internal Contact Info:
Phone: 467-7374
Website:
http://pharmadevelopment.roche.com/index/pdb/pdb-functional-groups/pdb-biostatistics/pdb-ncb-home.htm
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