[R] create new column to combine 2 data.frames

[Rui Barradas]

Hello,

Ok, try instead



library(reshape2)
tmp <- dcast(data = dat2, ID ~ Type, value.var = "Type")

tmp[-1] <- lapply(tmp[-1], function(x){
	y <- integer(length(x))
	s <- as.character(x[!is.na(x)])[1]
	idx <- which(as.character(dat2[["Type"]]) == s)
	y[!is.na(x)] <- dat2[["Days"]][idx]
	y})

result <- merge(dat1, tmp)
result


Rui Barradas

Em 30-08-2013 10:27, Mat escreveu:
> Thanks first.
>
> that doesn't look bad. But if have a equal ID in dat2, the days are no
> longer correct.
>
> the correct data.frame has to look like this one:
>
>    ID Name Management Training
> 1  1 Jack          1        3
> 2  2 John          1        0
> 3  3 Jill          0        4
>
> not this one:
>
>    ID Name Management Training
> 1  1 Jack          1        1
> 2  2 John          3        0
> 3  3 Jill          0        1
>
>> dat1 <- read.table(text = "
> + ID Name
> + 1  Jack
> + 2  John
> + 3  Jill
> + ", header = TRUE, stringsAsFactors = FALSE)
>>
>> dat2 <- read.table(text = "
> + ID  Days  Type
> + 1    1       Management
> + 1    3       Training
> + 2    1       Management
> + 3    4       Training
> + ", header = TRUE, stringsAsFactors = FALSE)
>>
>> library(reshape2)
>> tmp <- dcast(data = dat2, ID ~ Type, value.var = "Type")
>>
>> tmp[-1] <- lapply(tmp[-1], function(x){
> + y <- integer(length(x))
> + y[!is.na(x)] <- dat2[["Days"]][!is.na(x)]
> + y})
>> result <- merge(dat1, tmp)
>> result
>    ID Name Management Training
> 1  1 Jack          1        1
> 2  2 John          3        0
> 3  3 Jill          0        1
>>
>
>
>
> --
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