[R] Extracting list names within a looped function
Berend Hasselman
bhh at xs4all.nl
Thu Nov 15 11:27:00 CET 2012
On 15-11-2012, at 11:14, Gaj Stan (BIGCAT) wrote:
> Hello all,
>
> I have the following problem:
>
> 1) A list was defined as 'a'
>
> a <- list("var1"=c(100:1), "var2"=c(1:100), "var3"=rnorm(100))
>
> 2) a function 'foo' was defined that extracts the variable name assigned to x using the deparse(substitute()) functionality. This name will then be used within the function to generate specific output files, etc.
>
> foo <- function(x) {
> print( deparse(substitute(x)) )
> }
>
> However, I am currently interested in looping through all list variables and extract the list variable name from within the function. The current loop (see below) will result in
>
> for(i in 1:length(a)) {
> foo(a[[i]])
> }
> [1] "a[[i]]"
>
> which actually does what I expected of deparse(substitute(x)), but is not what I wanted. I would like to end up with something like
>
> [1] "var1"
> [1] "var2"
> [1] "var3"
>
> or
>
> [1] "a[[\"var1\"]]"
> [1] "a[[\"var2\"]]"
> [1] "a[[\"var3\"]]"
>
> Keep in mind that x has to be a matrix, and not a list. This to keep the function as general as possible.
>
> Does anyone have any idea on how to tackle this? Is deparse(substitute(x)) here the best way to go? Are there alternatives?
I'm not sure if I understand what you want but will this give you what you seem to want:
names(a)
Berend
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