[R] replacement has length zero

[Jeff Newmiller]

Your request fails the reproducibility requirement from the posting guide, because you have not supplied enough data to run the code and reproduce the error.
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Sent from my phone. Please excuse my brevity.

fabiano <chimbioputo at gmail.com> wrote:

>I have been working on the following code but keep getting an err
>message. My
>current thinking is that the problem is on the indexing but do not know
>how
>to fix it. Any help please?
>
>ungulate <- read.csv("Ungulate.csv",row.names=1)
>ungulate <-
>as.matrix(ungulate);colnames(ungulate)<-NULL;rownames(ungulate)<-NULL
>habitat <- read.csv("Ungulate_vegetation.csv")
>habitat <- habitat[,3]
>site.data <- read.csv("Ungulate_site.csv")
>site <- site.data$SiteId
>visit <- site.data$Visit
>date <- site.data$Date
>date <- matrix(date,nrow=20,ncol=7,byrow=TRUE)
>S <- dim(ungulate)[1]
>m <- 14	# number of augmented species
>G <- read.csv("Ungulate_group.csv")
>G <- G[,2]
>g <- rep(NA,length=m)
>G <- c(G,g) # combined list with actual and augmented data set so in
>this
>case 6 + 14 
>g <- length(table(G))
># habitat id
>Hab <- cbind(seq(1,20),habitat) #habitat types for 20 sties run from 2
>to 4
>
>hab <- matrix(NA,nrow=2,ncol=7)    #creating placing values to be
>filled
>with values generated by the following loop
>for(i in 1:4){
>	hab[i,] <- Hab[habitat==i,1]   }   # want to use this loop to
>substitute NA
>by exact values as those found in the real data set which can be 2 to 4
>but
>keep getting an error message saying 
>
>Error in hab[i, ] <- Hab[habitat == i, 1] : replacement has length zero
>
>Any help. Thanks
>Error in hab[i, ] <- Hab[habitat == i, 1] : replacement has length zero
>
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