[R] rank with uniform count for each rank

[Sarah Goslee]

Hi,

On Wed, Feb 22, 2012 at 4:01 PM, Ben quant <ccquant at gmail.com> wrote:
> Hello,
>
> What is the best way to get ranks for a vector of values, limit the range
> of rank values and create equal count in each group? I call this uniform
> ranking...uniform count/number in each group.
>
> Here is an example using three groups:
>
> Say I have values:
> x = c(3, 2, -3, 1, 0, 5, 10, 30, -1, 4)
> names(x) = letters[1:10]
>> x
> a  b  c  d  e  f   g   h   i   j
> 3  2 -3  1  0  5 10 30 -1  4
> I would like:
> a  b  c  d  e  f  g  h  i  j
> 2  2  1  2  1  3 3  3  1 3
>
> Same thing as above, maybe easier to see:
>  c   i  e  d  b  a   j   f  g   h
> -3 -1  0  1  2  3  4  5 10 30
> I would get:
> c  i e d b a  j f  g h
> 1 1 1 2 2 2 3 3 3 3

Thanks for the clear example.

> Note that there are 4 values with a rank of 3 because I can't get even
> numbers (10/3 = 3.333).
>
> Been to ?sort, ?order, ?quantile, ?cut, and ?split.

What's wrong with:

as.numeric(cut(x, c(min(x)-1, quantile(x, .33), quantile(x, .66), max(x) + 1)))
 [1] 1 1 1 2 2 2 3 3 3 3

Sarah


-- 
Sarah Goslee
http://www.functionaldiversity.org