[R] split character line into rows
arun
smartpink111 at yahoo.com
Mon Dec 17 22:58:09 CET 2012
Hi,
This could be read using the first method I suggested. The ?substr() method was suggested as I thought that there will be square brackets in each line.
dat1<-read.table("preila.txt",sep="",header=FALSE,fill=TRUE,dec=",",stringsAsFactors=FALSE)
dat2<-na.omit(dat1)
dat2$Date<-as.POSIXct(paste(dat2$V1,dat2$V2,sep=" "),format="%Y.%m.%d %H:%M:%S")
dat3<-dat2[,c(6,3:5)]
colnames(dat3)[2:4]<-paste0("V",2:4)
str(dat3)
#'data.frame': 1437 obs. of 4 variables:
# $ Date: POSIXct, format: "2010-12-26 00:00:52" "2010-12-26 00:01:52" ...
# $ V2 : num 689 696 712 721 726 ...
# $ V3 : num 11.7 11.7 11.7 11.7 11.7 ...
# $ V4 : num 43 43 43 43 43 43 43 43 43 43 ...
row.names(dat3)<-1:nrow(dat3)
head(dat3)
# Date V2 V3 V4
#1 2010-12-26 00:00:52 688.88 11.69 43
#2 2010-12-26 00:01:52 696.19 11.69 43
#3 2010-12-26 00:02:52 712.26 11.69 43
#4 2010-12-26 00:03:52 720.70 11.69 43
#5 2010-12-26 00:04:52 726.16 11.69 43
#6 2010-12-26 00:05:52 713.26 11.69 43
A.K.
________________________________
From: Simonas Kecorius <simolas2008 at gmail.com>
To: arun <smartpink111 at yahoo.com>
Sent: Monday, December 17, 2012 4:41 PM
Subject: Re: [R] split character line into rows
Hey Arun,
thanks for quick response and your kind help. I appreciate it a lot.
When I input data as you have written me, there is no problem. It separates by it self. But when I try to read data from txt file, everything goes wrong...
I add you a raw txt data. Maybe it would help.
Thanks a lot for your attempts to solve my problems.
p.s. dont know how to write back to my own post, therefore I wrote straight to your mail. Sorry for that.
2012/12/17 arun <smartpink111 at yahoo.com>
Hi,
>This could also work:
> max(nchar(txt))
>#[1] 58
>res<-read.table(text=substr(txt[nchar(txt)>20],5,58),sep="",dec=",",header=FALSE,stringsAsFactors=FALSE)
> res
># V1 V2 V3 V4 V5
>#1 2010.12.26 00:00:52 688.88 11.69 43
>#2 2010.12.26 00:01:52 696.19 11.69 43
>
>A.K.
>
>
>
>
>----- Original Message -----
>
>From: David Winsemius <dwinsemius at comcast.net>
>To: Simonas Kecorius <simolas2008 at gmail.com>
>Cc: r-help at r-project.org
>Sent: Monday, December 17, 2012 3:15 PM
>Subject: Re: [R] split character line into rows
>
>
>On Dec 17, 2012, at 4:04 AM, Simonas Kecorius wrote:
>
>> Hey R users,
>>
>> suppose we have data:
>>
>txt <- readLines(textConnection("[1] 2010.12.26 00:00:52 688,88 11,69 43,00
>[2] 11,69 43,00
>[3] 11,69 43,00
>[4] 11,69 43,00
>[5] 11,69 43,00
>[6] 11,69 43,00
>[7] 11,69 43,00
>[8] 11,69 43,00
>[9] 11,69 43,00
>[10] 11,69 43,00
>[11] 11,69 43,00
>[12] 11,69 43,00
>[13] 11,69 43,00
>[14] 11,69 43,00
>[15] 11,69 43,00
>[16] 11,69 43,00
>[17] 11,69 43,00
>[18] 11,69 43,00
>[19] 11,69 43,00
>[20] 11,69 43,00
>[21] 11,69 43,00
>[22] 11,69 43,00
>[23] 11,69 43,00
>[24] 11,69 43,00
>[25] 11,69 43,00
>[26] 11,69 43,00
>[27] 11,69 43,00
>[28] 11,69 43,00
>[29] 11,69 43,00
>[30] 11,69 43,00
>[31] 11,69 43,00
>[32] 11,69 43,00
>[33] 11,69 43,00
>[34] 11,69 43,00
>[35] 11,69 43,00
>[36] 11,69 43,00
>[37] 11,69 43,00
>[38] 11,69 43,00
>[39] 11,69 43,00
>[40] 11,69 43,00
>[41] 11,69 43,00
>[42] 11,69 43,00
>[43] 11,69 43,00
>[44] 11,69 43,00
>[45] 11,69 43,00
>[46] 11,69 43,00
>[47] 11,69 43,00
>[48] 11,69 43,00
>[49] 11,69 43,00
>[50] 11,69 43,00
>[51] 11,69 43,00
>[52] 11,69 43,00
>[53] 11,69 43,00
>[54] 11,69 43,00
>[55] 11,69 43,00
>[56] 11,69 43,00
>[57] 11,69 43,00
>[58] 11,69 43,00
>[59] 11,69 43,00
>[60] 11,69 43,00
>[61] 2010.12.26 00:01:52 696,19 11,69 43,00
>[62] 11,69 43,00
>[63] 11,69 43,00
>[64] 11,69 43,00
>[65] 11,69 43,00
>[66] 11,69 43,00"))
>
>txt <- sub("\\[.+\\]","", txt)
>read.table(text=txt[ grepl("[[:digit:]]{4}\\.", txt) ] )
> V1 V2 V3 V4 V5
>1 2010.12.26 00:00:52 688,88 11,69 43,00
>2 2010.12.26 00:01:52 696,19 11,69 43,00
>
>Since you seemed to be using commas for decimal points I thought search for "NNNN." as a pattern might be sufficient, but you could extend that to a full date matching pattern if needed.
>
>
>> ..................................... etc.
>>
>> Is there a way to split data into date column, V2, V3 and V4 columns and
>> erase those lines without date, so that data would look like that:
>>
>> date V2 V3 V4
>> 2010.12.26 00:01:52 555 11.67 44
>> 2010.12.26 00:02:52 566 11.67 44
>>
>> etc.
>>
>> Thanks a lot!
>>
>>
>> --
>> Simonas Kecorius
>> **
>>
>> [[alternative HTML version deleted]]
>
>Please read the Posting Guide and learn to post in plain text.
>
>
>David Winsemius
>Alameda, CA, USA
>
>
>______________________________________________
>R-help at r-project.org mailing list
>https://stat.ethz.ch/mailman/listinfo/r-help
>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>and provide commented, minimal, self-contained, reproducible code.
>
>
--
Simonas Kecorius
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