[R] Assignment of values with different indexes
David Winsemius
dwinsemius at comcast.net
Thu Dec 6 04:39:48 CET 2012
On Dec 5, 2012, at 6:47 PM, Brian Feeny wrote:
>
> I would like to take the values of observations and map them to a
> new index. I am not sure how to accomplish this. The result would
> look like so:
>
> x[1,2,3,4,5,6,7,8,9,10]
> becomes
> y[2,4,6,8,10,12,14,16,18,20]
This suggests to me that you are having difficulty transfering your
Matlab knowldege to R.
>
> The "newindex" would not necessarily be this sequence, but a
> sequence I have stored in a vector, so it could be all kinds of
> values. here is what happens:
>
>> x <- rnorm(10)
>> myindex <- seq(from = 1,to = 20, by = 2)
>> y <- numeric()
>> y[myindex] <- x
>> y
> [1] -0.03745988 NA -0.09078822 NA
> 0.92484413 NA 0.32057426 NA
> [9] 0.01536279 NA 0.02200198 NA
> 0.37535438 NA 1.46606535 NA
> [17] 1.44855796 NA -0.05048738
>
> So yes, it maps the values to my new indexes, but I have NA's. The
> result I want would look like this instead:
The only structure in R that allows NULL values is a list. Matrices
need to have either value or NA.
>
>
> [1] -0.03745988
> [3] -0.09078822
> [5] 0.92484413
> [7] 0.32057426
> [9] 0.01536279
> [11] 0.02200198
> [13] 0.37535438
> [15] 1.46606535
> [17] 1.44855796
> [19] -0.05048738
>
>
> and remove the NA's. I tried this with na.omit() on x, but it looks
> like so:
>
>> x <- rnorm(10)
>> myindex <- seq(from = 1,to = 20, by = 2)
>> y <- numeric()
>> y[myindex] <- na.omit(x)
>> y
> [1] 0.87399523 NA -0.39908184 NA
> 0.14583051 NA 0.01850755 NA
> [9] -0.47413632 NA 0.88410517 NA
> -1.64939190 NA 0.57650807 NA
> [17] 0.44016971 NA -0.56313802
However it will not display the way you were inteniding:
> y <- list()
> y[seq(1,20, by=2)] <- 1:10
> y
[[1]]
[1] 1
[[2]]
NULL
[[3]]
[1] 2
[[4]]
NULL
[[5]]
[1] 3
snipped
--
David.
>
> Brian
>
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> and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
Alameda, CA, USA
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