[R] An infinite recursion error please explain!
Uwe Ligges
ligges at statistik.tu-dortmund.de
Sun Jul 24 17:38:36 CEST 2011
On 23.07.2011 04:29, mousy0815 wrote:
> Probability<- function(N, f, w, b, y, t, q) {
> #N is the number of lymph nodes
> #f is the fraction of Dendritic cells (in the correct node) that have the
> antigen
> #w is time in terms of hours
> #b is the starting position (somewhere in the node or somewhere in the gap
> between nodes. It is a number between 1 and (x+t))
> #y is the number of time steps it takes to traverse the gap (8hr/y)
> #t is the number of time steps it takes to traverse a node. (24hours total
> -- so 24hr/t)
> #q is the length of the time step
>
> m<- ceiling(w/q)
> A<- 1/N
> B<- 1-A
> C<- 1-f
> D<- (((m+b-1)%%(y+t))+1)
>
>
>
> if (b<=t) {########starts inside node
> if (m<=(t-b)){return(B + A*(C^m))} # start& end in first node
> if (D<=t) { # we finish in a node
> a<- (B + A*(C^(t-b))) #first node
> b<- ((B + A*(C^t))^(floor((m+b)/(y+t))-1)) # intermediate nodes (if
> any)
> c<- (B + A*(C^D)) # last node
> return(a*b*c)
> } else {return(Probability(N, f, ((m*q)-q), b, y, t, q))} ## finish in a
> gap
> } else {###### starts outside node
> if (m<=(y+t-b)) {return(1)} #also end in the gap
> if (D<=t) { #end in a node
> b<- ((B + A*(C^t))^(floor((m/(y+t)))))
> c<- (B + (A*(C^D)))
> return(b*c)
> } else {return(Probability(N, f, ((m*q)-q), b, y, t, q))} #outside node
> }
> }
>
>
> This works for most values of 'w' (time):
>
>> Probability(100, 0.001, 1, 1, 20, 20, (10/60))
> [1] 0.9999401
>> Probability(100, 0.001, 2, 1, 20, 20, (10/60))
> [1] 0.9998807
>> Probability(100, 0.001, 3, 1, 20, 20, (10/60))
> [1] 0.9998215
>> Probability(100, 0.001, 4, 1, 20, 20, (10/60))
> Error: evaluation nested too deeply: infinite recursion /
> options(expressions=)?
>
> But once I get to w=4 I get an infinite recursion. I get that there is a
> recursion in my function but I'm not sure why it wouldn't work. After a
> certain point (D<=t) would be true.
Maybe that certain point is nested rather deeply in your recursion (if
it actually exists, which I have not checked). If you change
options(expressions) to allow for a deeper recursion you end in a
protection stack overflow. Therefore it is obviously advisable to use an
iterative approach here.
Best,
Uwe Ligges
> Any help, please?
>
> --
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>
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