[R] replacing elements of a zoo object
David Winsemius
dwinsemius at comcast.net
Mon Aug 29 22:00:45 CEST 2011
On Aug 29, 2011, at 3:33 PM, R. Michael Weylandt wrote:
> Hmm, I don't know what this means as trouble shooting, but I get the
> following:
>
> snipped
> 4
> > x[as.Date('2001-01-05')] = 0
> > x
> Error in dimnames(x) <- dn :
> length of 'dimnames' [1] not equal to array extent
> > str(x)
> ‘zoo’ series from 2001-01-02 to 2001-01-06
> Data: num [1:11327] 1 2 3 4 5 NA NA NA NA NA ...
^^^^^^
> Index: Class 'Date' num [1:5] 11324 11325 11326 11327 11328
> >
> difftime(as.Date("1970-01-01"), as.Date("2001-01-05"))
Time difference of -11327 days
Notice that some buggy interaction of mismatched package versions
managed to get the internal integer representation of a Date classed
variable confused with a length. I see this as of trifling interest at
best. That nice police officer over there is telling us: "Nothing to
see here folks, move on; please stop blocking the sidewalk."
>
>
> Obviously this is hard for anyone to troubleshoot if you can't
> reproduce it. I get the same error in R versions 12.0 and 13.0
> (although I don't get the "warning zoo was built under R 13.1"
> warning when I use zoo in R 12.0)
>
>
>
> On Mon, Aug 29, 2011 at 2:07 PM, Gene Leynes <gleynes+r at gmail.com>
> wrote:
> Michael,
>
> By the way, although I replied to David's email, I was responding to
> you as well. Your results were exactly what I was expecting, but I
> didn't get your results.
>
>
>
> On Mon, Aug 29, 2011 at 1:51 PM, R. Michael Weylandt <michael.weylandt at gmail.com
> > wrote:
> How exactly do you mean it doesn't work? Copied from my GUI:
>
> > x = zoo(1:5, as.Date('2001-01-01')+1:5)
> > x[as.Date('2001-01-05')]
> 2001-01-05
> 4
> > x[as.Date('2001-01-05')] = 0
> > x
> 2001-01-02 2001-01-03 2001-01-04 2001-01-05 2001-01-06
> 1 2 3 0 5
>
> (Those actually line up correctly on my machine..)
>
> Michael Weylandt
>
> On Mon, Aug 29, 2011 at 2:45 PM, Gene Leynes <gleynes+r at gmail.com>
> wrote:
> Why doesn't this work?
>
> x = zoo(1:5, as.Date('2001-01-01')+1:5)
> x[as.Date('2001-01-05')]
> x[as.Date('2001-01-05')] = 0
> x
>
>
> I think this is especially bad because it doesn't cause an error.
> It lets
> you do something to x, but then you can't see x again to see what it
> did.
>
> [[alternative HTML version deleted]]
>
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>
>
David Winsemius, MD
West Hartford, CT
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