[R] lattice xscale.components: different ticks on top/bottom axis

Boris.Vasiliev at forces.gc.ca Boris.Vasiliev at forces.gc.ca
Fri Apr 1 21:59:11 CEST 2011


> On Fri, Mar 11, 2011 at 12:28 AM,  
> <Boris.Vasiliev at forces.gc.ca> wrote:
> > Good afternoon,
> >
> > I am trying to create a plot where the bottom and top axes have the 
> > same scale but different tick marks.  I tried user-defined 
> > xscale.component function but it does not produce desired results.  
> > Can anybody suggest where my use of xscale.component 
> > function is incorrect?
> >
> > For example, the code below tries to create a plot where horizontal 
> > axes limits are c(0,10), top axis has ticks at odd integers, and 
> > bottom axis has ticks at even integers.
> >
> > library(lattice)
> >
> > df <- data.frame(x=1:10,y=1:10)
> >
> > xscale.components.A <- function(...,user.value=NULL) {
> >  # get default axes definition list; print user.value
> >  ans <- xscale.components.default(...)
> >  print(user.value)
> >
> >  # start with the same definition of bottom and top axes
> >  ans$top <- ans$bottom
> >
> >  # - bottom labels
> >  ans$bottom$labels$at <- seq(0,10,by=2)
> >  ans$bottom$labels$labels <- paste("B",seq(0,10,by=2),sep="-")
> >
> >  # - top labels
> >  ans$top$labels$at <- seq(1,9,by=2)
> >  ans$top$labels$labels <- paste("T",seq(1,9,by=2),sep="-")
> >
> >  # return axes definition list
> >  return(ans)
> > }
> >
> > oltc <- xyplot(y~x,data=df,
> >
> > scales=list(x=list(limits=c(0,10),at=0:10,alternating=3)),
> >               xscale.components=xscale.components.A,
> >               user.value=1)
> > print(oltc)
> >
> > The code generates a figure with incorrectly placed bottom and top 
> > labels.  Bottom labels "B-0", "B-2", ... are at 0, 1, ... and top 
> > labels "T-1", "T-3", ... are at 0, 1, ...  When axis-function runs out 
> > of labels, it replaces labels with NA.
> >
> > It appears that lattice uses top$ticks$at to place labels and 
> > top$labels$labels for labels.  Is there a way to override this 
> > behaviour (other than to expand the "labels$labels" vector to be as 
> > long as "ticks$at" vector and set necessary elements to "")?
> 
> Well, <top|bottom>$ticks$at is used to place the ticks, and 
> $labels$at is used to place the labels. They should typically 
> be the same, but you have changed one and not the other. 
> Everything seems to work if you set $ticks$at to the same 
> values as $labels$at:
> 
> 
>     ##  - bottom labels
> +   ans$bottom$ticks$at <- seq(0,10,by=2)
>     ans$bottom$labels$at <- seq(0,10,by=2)
>     ans$bottom$labels$labels <- paste("B",seq(0,10,by=2),sep="-")
> 
>     ##  - top labels
> +   ans$top$ticks$at <- seq(1,9,by=2)
>     ans$top$labels$at <- seq(1,9,by=2)
>     ans$top$labels$labels <- paste("T",seq(1,9,by=2),sep="-")
> 
> 
> > Also, can user-parameter be passed into xscale.components() 
> > function? (For example, locations and labels of ticks on the top 
> > axis).  In the  code above, print(user.value) returns NULL even 
> > though in the xyplot() call user.value is 1.
> 
> No. Unrecognized arguments are passed to the panel function 
> only, not to any other function. However, you can always 
> define an inline
> function:
> 
> oltc <- xyplot(y~x,data=df,
>                scales=list(x=list(limits=c(0,10), at = 0:10, 
>                            alternating=3)),
>                xscale.components = function(...) 
>                            xscale.components.A(..., user.value=1))
> 
> Hope that helps (and sorry for the late reply).
> 
> -Deepayan
> 

Deepyan,

Thank you very much for your reply.  It makes things a bit clearer.  

It other words in the list prepared by xscale.components(), vectors <top|bottom>$ticks$at and <top|bottom>$labels$at must be the same.  If only every second tick is to be labelled then every second label should be set explicitly to empty strings:

  ans$bottom$ticks$at <- seq(0,10,by=1)
  ans$bottom$labels$at <- seq(0,10,by=1)
  ans$bottom$labels$labels <- paste("B",seq(0,10,by=1),sep="-")
  # replace  "B-1", "B-3", ... with ""
  ans$bottom$labels$labels[seq(2,11,by=2)] <- ""

Sincerely,
Boris.



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