[R] count frequency
Rainer M Krug
r.m.krug at gmail.com
Fri Sep 17 14:26:44 CEST 2010
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On 17/09/10 14:19, Alaios wrote:
> Hello everyone,
> please consider the following lines of a matrix
>
>
> [574,] 59 32
> [575,] 59 32
> [576,] 59 32
> [577,] 59 32
> [578,] 59 32
> [579,] 59 32
> [580,] 59 32
> [581,] 60 32
> [582,] 60 33
> [583,] 60 33
> [584,] 60 33
> [585,] 60 33
> [586,] 60 33
> [587,] 60 33
> [588,] 60 33
> [589,] 60 33
> [590,] 60 33
> [591,] 61 33
> [592,] 61 33
> [593,] 61 33
> [594,] 61 33
> [595,] 61 33
> [596,] 61 33
> [597,] 61 33
> [598,] 61 33
> [599,] 61 33
> [600,] 61 33
> [601,] 62 34
>
> Is it possible somehow to count the similarities between the first and second
> column and put them on a third column like this?
>
> 59 32 3
> 60 33 5
> 62 34 1
>
> where (3,5,1 are the frequencies for (59,32), (60,33) and (62,34)
One solution:
> x <- data.frame(a=trunc(runif(10)*10), b=trunc(runif(10)*10))
> x
a b
1 6 5
2 7 5
3 1 5
4 0 4
5 3 9
6 6 8
7 4 3
8 0 4
9 2 7
10 7 2
> x$comb <- paste(x$a, x$b)
> x
a b comb
1 6 5 6 5
2 7 5 7 5
3 1 5 1 5
4 0 4 0 4
5 3 9 3 9
6 6 8 6 8
7 4 3 4 3
8 0 4 0 4
9 2 7 2 7
10 7 2 7 2
> table(x$comb)
0 4 1 5 2 7 3 9 4 3 6 5 6 8 7 2 7 5
2 1 1 1 1 1 1 1 1
>
I am sure, there are better ones
Cheers,
Rainer
>
> Best Regards
> Alex
>
>
>
>
> [[alternative HTML version deleted]]
>
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> and provide commented, minimal, self-contained, reproducible code.
- --
Rainer M. Krug, PhD (Conservation Ecology, SUN), MSc (Conservation
Biology, UCT), Dipl. Phys. (Germany)
Centre of Excellence for Invasion Biology
Natural Sciences Building
Office Suite 2039
Stellenbosch University
Main Campus, Merriman Avenue
Stellenbosch
South Africa
Tel: +33 - (0)9 53 10 27 44
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email: Rainer at krugs.de
Skype: RMkrug
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