[R] numerical derivative R help
Ravi Varadhan
rvaradhan at jhmi.edu
Wed Jul 7 01:46:10 CEST 2010
Please do not do multiple postings.
You do not need numerical derivative, but a refresher course in calculus.
fitterma.deriv <- function(xtime) {
a <- -0.09144115
b <- -0.01335756
c <- -2.368057
d <- -0.00600052
deriv <- b * exp(a + b*xtime) + d * exp(c + d * xtime)
return(deriv)
}
require(numDeriv)
xtime <- seq(0, 1, length=100)
deriv.exact <- fitterma.deriv(xtime)
deriv.num <- grad(x=xtime, func=fitterma)
> all.equal(deriv.exact, deriv.num)
[1] TRUE
>
Hope this is helpful,
Ravi.
____________________________________________________________________
Ravi Varadhan, Ph.D.
Assistant Professor,
Division of Geriatric Medicine and Gerontology
School of Medicine
Johns Hopkins University
Ph. (410) 502-2619
email: rvaradhan at jhmi.edu
----- Original Message -----
From: Parminder Mankoo <pkmankoo09 at gmail.com>
Date: Tuesday, July 6, 2010 7:03 pm
Subject: [R] numerical derivative R help
To: r-help at r-project.org
> I fit my CDF to sum of exponentials and now I want to take the numerical
> derivative of this function to obtain probability density.I will really
> appreciate your help reagrding the error messages I am getting which
> I don't
> understand.
>
> *
> *
>
> > fitterma <- function(xtime) {
>
> a <- -0.09144115
>
> b <- -0.01335756
>
> c <- -2.368057
>
> d <- -0.00600052
>
> return(exp(a+b*xtime)+exp(c+d*xtime))
>
> }
>
>
> > numericDeriv(fitterma,"xtime")
>
>
> *Error in numericDeriv(fitterma, "xtime") : *
>
> * cannot coerce type 'closure' to vector of type 'double'*
>
> *
> *
>
> *Thanks,*
>
> *parmee*
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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>
> PLEASE do read the posting guide
> and provide commented, minimal, self-contained, reproducible code.
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