[R] tapply for function taking of >1 argument?

[Petr PIKAL]

Hi

r-help-bounces at r-project.org napsal dne 02.02.2010 22:16:06:

> 
> 'fraid not :-((
> 
> tapply( data, groups, weighted.mean, weights) 

tapply(seq(along=lll), rrr, function(i, x, w) weighted.mean(x[i], w[i]), 
       x=lll, w=ttt) 
If you want to subset more than one thing, subset the index vector. 
The above help I obtained from Prof.Ripley several years ago so (untested)

tapply( seq(along=data), groups, function (i, x, w) weighted.mean(x[i], 
w[i]), x=data, w=weights)

I believe it shall still work.

Regards
Petr



> 
> won't work because the *entire* weights vector is passed as the 2nd arg 
to
> weighted.means. But weighted.mean needs 'weights' to be split in the 
same
> way as 'data' -- the first and 2nd args need to correspond. 
> 
> 
> Jorge Ivan Velez wrote:
> > 
> > Hi sjaffem,
> > 
> > You were almost there:
> > 
> > tapply( yourdata, groups, weighted.mean, weights)
> > 
> > See ?tapply for more information.
> > 
> > HTH,
> > Jorge
> > 
> > 
> > 
> 
> -- 
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> of-1-argument-tp1460392p1460419.html
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> 
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