[R] Time out for a R Function

[Mike Marchywka]

----------------------------------------
> Date: Tue, 7 Dec 2010 16:11:42 +1100
> From: michael.bedward at gmail.com
> To: santosh.srinivas at gmail.com; r-help at r-project.org
> Subject: Re: [R] Time out for a R Function
>
> Below is a toy function with one way of doing it. There are bound to
> be better ways :)

This seems to just check total time on each iteration.
Presumably for this you would be better off setting an
ieration limit, not a timeout. A watchdog timer to insure
that pretend task doesn't hang would need another thread
and you would either need the target task to check
a shared variable that you set from the watchdog or
you just kill the target thread from watchdog but
this may be hard to do in a way that lets you continue
in any meaningful way. 



>
> function(niter = 10, time.out = 3) {
> pretend.task <- function() {
> Sys.sleep(0.5)
> }
>
> start <- proc.time()
>
> for (iter in 1:niter) {
> pretend.task()
> cur <- proc.time() - start
> if (cur[3] > time.out) return("timed out")
> }
>
> return("completed")
> }
>
>
> On 7 December 2010 13:04, Santosh Srinivas  wrote:
> > Hello Group,
> >
> > I have an R-function that works fine for most part but sometime runs into a
> > long loop! (I'm lazy and short on time to debug right now so want to do
> > something easy)
> > For my purpose, it is ok to make few errors .... is there a way I can put a
> > timeout on a function and the r-process needes to move on to the next step?
> >
> > Thank you.
> > S
> >
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> >
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.