[R] str: how to use "no list" recursively?

[Henrique Dallazuanna]

Try this:

cat(gsub(":List of .*", "", capture.output(str(x, no.list = TRUE))), sep = '\n')

On Fri, Apr 9, 2010 at 11:11 PM, Jeff Brown <dopethatwantscash at yahoo.com> wrote:
>
> Hi,
>
> In the help file for str(), the following line appears: "no.list         logical;
> if true, no ‘list of ...’ nor the class are printed".  However, that appears
> to be true only on the top level; setting no.list to TRUE still leaves the
> remaining levels with the `list of ...' statement intact:
>
>> x <- list(
> +       a = list(list()),
> +       b = list(list())
> + );
>> str(x)
> List of 2
>  $ a:List of 1
>  ..$ : list()
>  $ b:List of 1
>  ..$ : list()
>> str(x, no.list = TRUE)
>  $ a:List of 1
>  ..$ : list()
>  $ b:List of 1
>  ..$ : list()
>>
>
> For readability reasons, I'd like to keep the indented $ signs and the names
> of the sub-lists but suppress printing of `List of ...'.  Is that possible?
>
> Thanks,
> Jeff
> --
> View this message in context: http://n4.nabble.com/str-how-to-use-no-list-recursively-tp1820073p1820073.html
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>
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>



-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O