[R] How do I specify a partially completed survival analysis model?
RWilliam
fujiening at hotmail.com
Fri Nov 20 17:07:01 CET 2009
In reply to suggestion by David W., setting an offset parameter doesn't seem
to work as R is not recognizing the "X2" part of coxph(
Surv(Time,Censor)~X1, offset=log(4.3*X2), data= a ). Also, here's some
sample data:
X1 X2 Time Censor
1 1 0.40619454 77.00666 0
2 1 0.20717868 100.00000 0
3 1 0.77360963 79.03463 1
4 1 0.62221954 100.00000 0
5 1 0.32191280 100.00000 0
6 1 0.73790704 72.84842 0
7 1 0.65012237 100.00000 0
8 1 0.71596105 100.00000 0
9 1 0.74787202 84.00172 0
10 1 0.66803790 41.65760 0
11 1 0.79922364 92.41999 0
12 1 0.76433736 90.99983 0
13 1 0.57014524 100.00000 0
14 1 0.39642235 100.00000 0
15 1 0.55756045 100.00000 0
16 0 0.60079340 100.00000 0
17 0 0.43630695 100.00000 0
18 0 0.09388013 100.00000 0
19 0 0.55956791 100.00000 0
20 0 0.52491597 97.71884 1
where we set the coefficient of X2 to be 8.
RWilliam wrote:
>
> Sorry for being impatient but is there really no way of doing this at all?
> It's quite urgent so any help is very much appreciated. Thank you.
>
>
>
> RWilliam wrote:
>>
>> Hello,
>>
>> I just started using R to do epidemiologic simulation research using the
>> Cox proportional hazard model. I have 2 covariates X1 and X2 which I want
>> to model as h(t,X)=h0(t)*exp(b1*X1+b2*X2). I assume independence of X
>> from t.
>>
>> After I simulate Time and Censor data vectors denoting the censoring time
>> and status respectively, I can call the following function to fit the
>> data into the Cox model (a is a data.frame containing 4 columns X1, X2,
>> Time and Censor):
>> b = coxph (Surv (Time, Censor) ~ X1 + X2, data = a, method = "breslow");
>>
>> Now the purpose of me doing simulation is that I have another mechanism
>> to generate the number b2. From the given b2 (say it's 4.3), Cox model
>> can be fit to generate b1 and check how feasible the new model is. Thus,
>> my question is, how do I specify such a model that is partially completed
>> (as in b2 is known). I tried things like Surv(Time,Censor)~X1+4.3*X2, but
>> it's not working. Thanks very much.
>>
>
>
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