[R] split strings

Monica Pisica pisicandru at hotmail.com
Wed May 27 14:33:46 CEST 2009


Hi,
 
Luckily for me - until now i did not have too many times to do these type of parsing - but who knows???  Up to now i was pretty happy with strsplit .....Anyway - thanks again for all the help, i really appreciate it.
 
Monica

----------------------------------------
> From: ggrothendieck at gmail.com
> Date: Tue, 26 May 2009 16:40:21 -0400
> Subject: Re: [R] split strings
> To: Waclaw.Marcin.Kusnierczyk at idi.ntnu.no
> CC: pisicandru at hotmail.com; r-help at r-project.org
>
> Although speed is really immaterial here this is likely
> to be faster than all shown so far:
>
> sub(".tif", "", basename(metr_list), fixed = TRUE)
>
> It does not allow file names with .tif in the middle
> of them since it will delete the first occurrence rather
> than the last but such a situation is highly unlikely.
>
>
> On Tue, May 26, 2009 at 4:24 PM, Wacek Kusnierczyk
> wrote:
>> Monica Pisica wrote:
>>> Hi everybody,
>>>
>>> Thank you for the suggestions and especially the explanation Waclaw provided for his code. Maybe one day i will be able to wrap my head around this.
>>>
>>> Thanks again,
>>>
>>
>> you're welcome. note that if efficiency is an issue, you'd better have
>> perl=TRUE there:
>>
>> output = sub('.*//(.*)[.]tif$', '\\1', input, perl=TRUE)
>>
>> with perl=TRUE, the one-pass solution is somewhat faster than the
>> two-pass solution of gabor's -- which, however, is probably easier to
>> understand; with perl=FALSE (the default), the performance drops:
>>
>> strings = sprintf(
>> 'f:/foo/bar//%s.tif',
>> replicate(1000, paste(sample(letters, 10), collapse='')))
>> library(rbenchmark)
>> benchmark(columns=c('test', 'elapsed'), replications=1000, order=NULL,
>> 'one-pass, perl'=sub('.*//(.*)[.]tif$', '\\1', strings, perl=TRUE),
>> 'two-pass, perl'=sub('.tif$', '', basename(strings), perl=TRUE),
>> 'one-pass, no perl'=sub('.*//(.*)[.]tif$', '\\1', strings,
>> perl=FALSE),
>> 'two-pass, no perl'=sub('.tif$', '', basename(strings), perl=FALSE))
>> # 1 one-pass, perl 3.391
>> # 2 two-pass, perl 4.944
>> # 3 one-pass, no perl 18.836
>> # 4 two-pass, no perl 5.191
>>
>> vQ
>>
>>
>>>
>>> Monica
>>>
>>> ----------------------------------------
>>>
>>>> Date: Tue, 26 May 2009 15:46:21 +0200
>>>> From: Waclaw.Marcin.Kusnierczyk at idi.ntnu.no
>>>> To: pisicandru at hotmail.com
>>>> CC: r-help at r-project.org
>>>> Subject: Re: [R] split strings
>>>>
>>>> Monica Pisica wrote:
>>>>
>>>>> Hi everybody,
>>>>>
>>>>> I have a vector of characters and i would like to extract certain parts. My vector is named metr_list:
>>>>>
>>>>> [1] "F:/Naval_Live_Oaks/2005/data//BE.tif"
>>>>> [2] "F:/Naval_Live_Oaks/2005/data//CH.tif"
>>>>> [3] "F:/Naval_Live_Oaks/2005/data//CRR.tif"
>>>>> [4] "F:/Naval_Live_Oaks/2005/data//HOME.tif"
>>>>>
>>>>> And i would like to extract BE, CH, CRR, and HOME in a different vector named "names.id"
>>>>>
>>>> one way that seems reasonable is to use sub:
>>>>
>>>> output = sub('.*//(.*)[.]tif$', '\\1', input)
>>>>
>>>> which says 'from each string remember the substring between the
>>>> rigthmost two slashes and a .tif extension, exclusive, and replace the
>>>> whole thing with the captured part'. if the pattern does not match, you
>>>> get the original input:
>>>>
>>>> sub('.*//(.*)[.]tif$', '\\1', 'f:/foo/bar//buz.tif')
>>>> # buz
>>>>
>>>> vQ
>>>>
>>> _________________________________________________________________
>>
>>




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