Hello: Is there a more natural way to get all elements that satisfy a condition when there are NAs in the sample? > x=c(1,2,NA) > x>=2 [1] FALSE TRUE NA > x[x>=2] [1] 2 NA ## I would expect here to get just "2" > x[!is.na(x) & x>=2] ## seems a bit cumbersome [1] 2 Thanks, Szilard