[R] last result

[Barry Rowlingson]

2009/1/23 Jorge Ivan Velez <jorgeivanvelez at gmail.com>:

> See ?.Last.value

 But don't do that right after you've done the calculation! You get
*one* chance with .Last.value:

 # here comes my important numbers...
 > runif(10)
  [1] 0.7685472 0.2301233 0.3053993 0.5185696 0.3345997 0.1544350 0.2663696
  [8] 0.3507546 0.5784584 0.8086018
 # oops, forgot to save. Rescue me!
 > .Last.value
  [1] 0.7685472 0.2301233 0.3053993 0.5185696 0.3345997 0.1544350 0.2663696
  [8] 0.3507546 0.5784584 0.8086018
 # great.

 # now lets do it again...
 # important numbers...
 > runif(10)
  [1] 0.93327031 0.83386334 0.12700277 0.64945395 0.69035166 0.03204482
  [7] 0.92048915 0.47846889 0.26652058 0.85651072
 # hmmm lets check the help:
 > ?.Last.value
 # great. but now:
 > .Last.value
 >
 it's gone! Oops.

Any typed expression that returns a value will stomp on .Last.value,
even if invisible (as returned from help()). Errors don't, so if you
can't remember if it's .Last.Value or .Last.value you're okay:

 > runif(10)
  [1] 0.9613436 0.5182666 0.1745280 0.5625401 0.7592582 0.6669713 0.2248729
  [8] 0.3458498 0.3198318 0.9048984
 > .Last.Value
 Error: object ".Last.Value" not found
 > .Last.value
  [1] 0.9613436 0.5182666 0.1745280 0.5625401 0.7592582 0.6669713 0.2248729
  [8] 0.3458498 0.3198318 0.9048984

 If this all fails, cut n paste the text and do it the old fashioned way...

Barry