[R] Regular expression to define contents between parentheses
Bert Gunter
gunter.berton at gene.com
Tue Aug 25 23:10:35 CEST 2009
Ha! Much better than mine and without PERL, to boot. Bravo Gabor!
-- Bert
Bert Gunter
Genentech Nonclinical Biostatisics
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On
Behalf Of Gabor Grothendieck
Sent: Tuesday, August 25, 2009 2:03 PM
To: Judith Flores
Cc: RHelp
Subject: Re: [R] Regular expression to define contents between parentheses
Instead of using .* use [^)]* so that you only get up to the next ) and also
it seems that you want to trim spaces so add space star at the beginning
and end:
gsub(" *\\([^)]*\\) *", "", myvector)
On Tue, Aug 25, 2009 at 4:17 PM, Judith Flores<juryef at yahoo.com> wrote:
> Hello dear R-helpers,
>
> I haven't been able to figure out of find a solution in the R-help
archives about how to delete all the characters contained in groups of
parenthesis. I have a vector that looks more or less like this:
>
> myvector<-c("something (80 km/h, sd) & more (6 kg/L,sd)", "somethingelse
(48 m/s, sd) & moretoo (50g/L , sd)")
>
> I want to extract all the strings that are not contained in parenthesis,
the goal would be to obtain the following new vector:
>
> subvector<-c("something & more", "somethingelse & moretoo")
>
> I tried the following, but this pattern seems to enclose all that is
included between the first opened parenthesis and the last closed
parethesis, which makes sense, but it's not what I need:
>
> subvector<-gsub("\\((.*)\\)","",myvector
>
>
> Your help will be very appreciated.
>
> Thank you,
>
> Judith
>
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>
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