[R] rnorm() converted to daily

Ken-JP kfmfe04 at gmail.com
Fri Apr 17 10:11:32 CEST 2009


I think I got it...

I assumed that n=100000 would be big enough to give me a sample mean which
converges on the population mean, but this was a bad assumption.

Using sigma / sqrt(n) for the standard error of the sample mean, I get...

-----------------------------------------------------

se.x.mean.as.perc.of.pop.mean <- (0.25 / sqrt(100000)) /0.08;  
se.y.mean.as.perc.of.pop.mean <- (0.25/sqrt(252)) / sqrt(100000)
/(0.08/252);

se.x.mean.as.perc.of.pop.mean   # 0.0098821
se.y.mean.as.perc.of.pop.mean   # 0.1568738

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